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Directions: Read the following information carefully and answer the question given below
Six students - A, B, C, D, E and F, got admission in different engineering colleges - BIT, PSIT, HBTI, KIT, JSS and AKG, not necessarily in same order, in the year 2018. Each college had different number of vacancies which was in multiples of 100 for every given college.
Maximum vacancies in any college were 600, in which F took admission and it is not KIT. C got admission in the college which has lowest vacancies and is not PSIT. JSS had vacancies double that of HBTI, in which A got admission. D took admission neither in AKG nor in PSIT. KIT has vacancies more than 300. Total vacancies of the colleges in which B and E took admission is 900, E's college having more vacancies. B took admission neither in KIT nor in PSIT.
Who took admission in AKG?
  • a)
    E
  • b)
    F
  • c)
    D
  • d)
    B
  • e)
    C
Correct answer is option 'E'. Can you explain this answer?
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Verified Answer
Directions: Read the following information carefully and answer the q...
Maximum vacancies in any college were 600, in which F took admission and is not KIT.
Thus, all colleges must have vacancies - 100, 200, 300, 400, 500 and 600.
Also,
C got admission in the college which has lowest vacancies i.e. 100.
JSS had vacancies double that of HBTI, in which A got admission.
Possible cases are:
HBTI = 100; JSS= 200 but this cannot be valid case as minimum vacancy is for C's college and HBTI is A's college.
Case I:
HBTI = 200; JSS= 400
Case II:
HBTI = 300; JSS= 600
Thus, we get,
Case I:
Case II:
Now,
Total vacancies of the colleges in which B and E took admission is 900, E's college having more vacancies.
Thus, cases can be:
B = 300; E = 600; but, this is not valid as F is already 600.
Thus, the valid case is:
B = 400; E= 500
We get,
Case I: (here JSS= 400)
Case II:
Since,
D took admission neither in AKG nor in PSIT.
So, D → BIT or KIT
But,
KIT has vacancies more than 300.
So, in both cases we get, D → BIT
B took admission neither in KIT nor in PSIT.
So, B took admission in AKG in case II. Also, in case II, E must have taken admission in KIT as vacancies are more than 300.
Also, in case I, E must have taken admission in KIT as F didn't take in KIT.
We get,
Case I:
Case II:
Now,
C didn't get admission in PSIT.
So, case II becomes invalid.
So, F must have taken admission in PSIT and C in AKG.
Final arrangement is as follows:
C took admission in AKG.
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Most Upvoted Answer
Directions: Read the following information carefully and answer the q...
Maximum vacancies in any college were 600, in which F took admission and is not KIT.
Thus, all colleges must have vacancies - 100, 200, 300, 400, 500 and 600.
Also,
C got admission in the college which has lowest vacancies i.e. 100.
JSS had vacancies double that of HBTI, in which A got admission.
Possible cases are:
HBTI = 100; JSS= 200 but this cannot be valid case as minimum vacancy is for C's college and HBTI is A's college.
Case I:
HBTI = 200; JSS= 400
Case II:
HBTI = 300; JSS= 600
Thus, we get,
Case I:
Case II:
Now,
Total vacancies of the colleges in which B and E took admission is 900, E's college having more vacancies.
Thus, cases can be:
B = 300; E = 600; but, this is not valid as F is already 600.
Thus, the valid case is:
B = 400; E= 500
We get,
Case I: (here JSS= 400)
Case II:
Since,
D took admission neither in AKG nor in PSIT.
So, D → BIT or KIT
But,
KIT has vacancies more than 300.
So, in both cases we get, D → BIT
B took admission neither in KIT nor in PSIT.
So, B took admission in AKG in case II. Also, in case II, E must have taken admission in KIT as vacancies are more than 300.
Also, in case I, E must have taken admission in KIT as F didn't take in KIT.
We get,
Case I:
Case II:
Now,
C didn't get admission in PSIT.
So, case II becomes invalid.
So, F must have taken admission in PSIT and C in AKG.
Final arrangement is as follows:
C took admission in AKG.
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Community Answer
Directions: Read the following information carefully and answer the q...


Explanation:

Given Information:
- F got admission in a college with maximum vacancies (600).
- C got admission in a college with lowest vacancies.
- A got admission in a college with vacancies double that of HBTI's vacancies.
- D did not get admission in AKG or PSIT.
- KIT has vacancies more than 300.
- Total vacancies of colleges where B and E got admission is 900, with E's college having more vacancies.
- B did not get admission in KIT or PSIT.

Analysis:
1. From the given information, we can deduce that A got admission in JSS, which has double the vacancies of HBTI.
2. F got admission in a college with 600 vacancies, which is not KIT.
3. C got admission in a college with the lowest vacancies, which is not PSIT.
4. D did not get admission in AKG or PSIT.
5. KIT has vacancies more than 300.
6. Total vacancies of colleges where B and E got admission is 900, with E's college having more vacancies.
7. B did not get admission in KIT or PSIT.

Solution:
- We know that F got admission in a college with 600 vacancies, and it is not KIT. So, F got admission in BIT.
- C got admission in a college with the lowest vacancies, which is not PSIT. Therefore, C got admission in HBTI.
- A got admission in a college with double the vacancies of HBTI, which is JSS.
- D did not get admission in AKG or PSIT. So, D got admission in KIT.
- From the information that E's college has more vacancies, and the total vacancies of B and E's colleges is 900, we can deduce that E got admission in AKG.
Therefore, the student who took admission in AKG is E.
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