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Directions: Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.
If Sohini reaches to point D from her house with shortest possible distance, the maximum distance by which the total travelling distance for Sohini reduces is:
  • a)
    √42km
  • b)
    (9-3√5) km
  • c)
    √45km
  • d)
    (10 - 2√10) km
  • e)
    (10 - 3√5)km
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Directions: Sohini starts walking in east direction and walks 1 km to...
The original distance Sohini would have travelled = 1 + 4 + 3 + 2 = 10 km
Shortest distance she can travel
Distance reduced = (10 - 2√10) km
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Most Upvoted Answer
Directions: Sohini starts walking in east direction and walks 1 km to...
To find the maximum distance by which the total traveling distance for Sohini reduces when she goes from her house to point D, we need to analyze the given directions and calculate the distances.

Let's break down the given directions step by step:

1) Sohini starts walking in the east direction and walks 1 km to reach point A.

2) Then she turns to her left and walks 4 km to reach point B.

3) Next, she turns to her left again and walks 3 km to reach point C.

4) From point C, she turns towards the right and walks 2 km to reach point D.

5) Finally, she turns towards the left direction again and walks 4 km to reach point E.

Now, let's calculate the total distance traveled by Sohini using the given directions:

- Distance from Sohini's house to point A: 1 km
- Distance from point A to point B: 4 km
- Distance from point B to point C: 3 km
- Distance from point C to point D: 2 km
- Distance from point D to point E: 4 km

Total distance traveled = 1 + 4 + 3 + 2 + 4 = 14 km

To find the maximum distance by which the total traveling distance reduces, we need to find an alternative route from Sohini's house to point D that is shorter than the given route.

Let's consider the alternate route:

1) Sohini starts walking in the east direction and walks 1 km to reach point A.

2) Then she turns to her left and walks 4 km to reach point B.

3) Next, she turns to her right and walks 3 km to reach point F (instead of point C).

4) From point F, she turns towards the right and walks 4 km to reach point G (instead of point D).

Using the Pythagorean theorem, we can calculate the distance between point B and point G as follows:

Distance between point B and point G = √[(3^2) + (4^2)] = √[9 + 16] = √25 = 5 km

Now, let's calculate the total distance traveled using the alternate route:

- Distance from Sohini's house to point A: 1 km
- Distance from point A to point B: 4 km
- Distance from point B to point G: 5 km

Total distance traveled = 1 + 4 + 5 = 10 km

Therefore, the maximum distance by which the total traveling distance for Sohini reduces is:

14 km - 10 km = 4 km

So the correct answer is option D) (10 - 2√10) km.
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Directions: Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.If Sohini reaches to point D from her house with shortest possible distance, the maximum distance by which the total travelling distance for Sohini reduces is:a)√42kmb)(9-3√5) kmc)√45kmd)(10 - 2√10) kme)(10 - 3√5)kmCorrect answer is option 'D'. Can you explain this answer?
Question Description
Directions: Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.If Sohini reaches to point D from her house with shortest possible distance, the maximum distance by which the total travelling distance for Sohini reduces is:a)√42kmb)(9-3√5) kmc)√45kmd)(10 - 2√10) kme)(10 - 3√5)kmCorrect answer is option 'D'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about Directions: Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.If Sohini reaches to point D from her house with shortest possible distance, the maximum distance by which the total travelling distance for Sohini reduces is:a)√42kmb)(9-3√5) kmc)√45kmd)(10 - 2√10) kme)(10 - 3√5)kmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions: Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.If Sohini reaches to point D from her house with shortest possible distance, the maximum distance by which the total travelling distance for Sohini reduces is:a)√42kmb)(9-3√5) kmc)√45kmd)(10 - 2√10) kme)(10 - 3√5)kmCorrect answer is option 'D'. Can you explain this answer?.
Solutions for Directions: Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.If Sohini reaches to point D from her house with shortest possible distance, the maximum distance by which the total travelling distance for Sohini reduces is:a)√42kmb)(9-3√5) kmc)√45kmd)(10 - 2√10) kme)(10 - 3√5)kmCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for CAT. Download more important topics, notes, lectures and mock test series for CAT Exam by signing up for free.
Here you can find the meaning of Directions: Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.If Sohini reaches to point D from her house with shortest possible distance, the maximum distance by which the total travelling distance for Sohini reduces is:a)√42kmb)(9-3√5) kmc)√45kmd)(10 - 2√10) kme)(10 - 3√5)kmCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Directions: Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.If Sohini reaches to point D from her house with shortest possible distance, the maximum distance by which the total travelling distance for Sohini reduces is:a)√42kmb)(9-3√5) kmc)√45kmd)(10 - 2√10) kme)(10 - 3√5)kmCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Directions: Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.If Sohini reaches to point D from her house with shortest possible distance, the maximum distance by which the total travelling distance for Sohini reduces is:a)√42kmb)(9-3√5) kmc)√45kmd)(10 - 2√10) kme)(10 - 3√5)kmCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Directions: Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.If Sohini reaches to point D from her house with shortest possible distance, the maximum distance by which the total travelling distance for Sohini reduces is:a)√42kmb)(9-3√5) kmc)√45kmd)(10 - 2√10) kme)(10 - 3√5)kmCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Directions: Sohini starts walking in east direction and walks 1 km to reach point A. Then she turns to her left and walks 4km to reach point B. Then she turns to her left and walks 3km to reach point C. Then she turns towards right and walks 2 km to reach point D. Then she turns towards left direction and walks 4km to reach point E.If Sohini reaches to point D from her house with shortest possible distance, the maximum distance by which the total travelling distance for Sohini reduces is:a)√42kmb)(9-3√5) kmc)√45kmd)(10 - 2√10) kme)(10 - 3√5)kmCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice CAT tests.
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