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(X 8)(X-10) find using Identity (X a)(X b)=Xsquare (a b)X ab?
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(X 8)(X-10) find using Identity (X a)(X b)=Xsquare (a b)X ab?
The identity used: (x+a) (x+b) = x²+(a+b)x+ab
the question given: (x+8) (x-10)
substitution: x²+(8-10)x+(8 x -10)
=x²-2x-80
Community Answer
(X 8)(X-10) find using Identity (X a)(X b)=Xsquare (a b)X ab?
Using the Identity (X a)(X b) = X^2 (a b) - X ab
Understanding the Identity:
- The given identity states that the product of two binomials in the form (X a) and (X b) can be simplified to X^2 times the product of the constants a and b minus X times the sum of the constants a and b.
Given Expression: (X + 8)(X - 10)
- Here, a = 8 and b = -10
Applying the Identity:
- X^2 (a b) - X ab
- X^2 (8 * -10) - X (8 + (-10))
- X^2 (-80) - X (-2)
- -80X^2 + 2X
Therefore, the simplified form of the expression (X + 8)(X - 10) using the given identity is -80X^2 + 2X.
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(X 8)(X-10) find using Identity (X a)(X b)=Xsquare (a b)X ab?
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