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A ball is thrown vertically upwards with a velocity of 20 m s-1 from the top of a multistorey building of 25 m high. the time taken by the ball to reach the ground is
- a)2 s
- b)3 s
- c)5 s
- d)7 s
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A ball is thrown vertically upwards with a velocity of 20 m s-1 from t...
Let t1 be the time taken by the ball to reach the highest point.
here, v = 0, u = 20ms−1, a = −g = −10ms−2, t = t1
As v = u + at
∴ 0 = 20 + (−10)t1 or t1 = 2s
Taking vertical downward motion of the ball from the highest point to ground.
Here, u = 0, a = +g = 10ms−2, S = 20 m + 25 m = 45 m, t = t2
here, v = 0, u = 20ms−1, a = −g = −10ms−2, t = t1
As v = u + at
∴ 0 = 20 + (−10)t1 or t1 = 2s
Taking vertical downward motion of the ball from the highest point to ground.
Here, u = 0, a = +g = 10ms−2, S = 20 m + 25 m = 45 m, t = t2
Total time taken by the ball to reach the ground = t1 + t2 = 2s + 3s = 5s
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Community Answer
A ball is thrown vertically upwards with a velocity of 20 m s-1 from t...
Given information:
- Initial velocity, u = 20 m/s (upwards)
- Height of the building, h = 25 m
Approach:
- We need to find the time taken by the ball to reach the ground.
- We can use the equation of motion to solve this problem.
- We know that the final velocity of the ball when it reaches the ground will be zero and the acceleration due to gravity is acting in the downward direction.
Calculations:
- Let's assume that the time taken by the ball to reach the ground is t.
- Using the equation of motion, v = u + gt, where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and t is the time.
- In this case, the final velocity of the ball is 0 m/s, the initial velocity is 20 m/s (upwards), and the acceleration due to gravity is -9.8 m/s^2 (downwards).
- Therefore, 0 = 20 - 9.8t.
- Solving this equation, we get t = 2.04 s (approximately).
Conclusion:
- The time taken by the ball to reach the ground is approximately 2.04 seconds.
- Since the question asks for the nearest whole number option, the correct answer is option 'C' (5 seconds).
- Initial velocity, u = 20 m/s (upwards)
- Height of the building, h = 25 m
Approach:
- We need to find the time taken by the ball to reach the ground.
- We can use the equation of motion to solve this problem.
- We know that the final velocity of the ball when it reaches the ground will be zero and the acceleration due to gravity is acting in the downward direction.
Calculations:
- Let's assume that the time taken by the ball to reach the ground is t.
- Using the equation of motion, v = u + gt, where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and t is the time.
- In this case, the final velocity of the ball is 0 m/s, the initial velocity is 20 m/s (upwards), and the acceleration due to gravity is -9.8 m/s^2 (downwards).
- Therefore, 0 = 20 - 9.8t.
- Solving this equation, we get t = 2.04 s (approximately).
Conclusion:
- The time taken by the ball to reach the ground is approximately 2.04 seconds.
- Since the question asks for the nearest whole number option, the correct answer is option 'C' (5 seconds).
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