A motorcycle and a car start from rest from the same place at the same...
When car overtakes motorcycle, both have travelled the same distance in the same time. Let the total distance travelled be S and the total time taken to overtake be t.
For motorcycle:Maximum speed attained = 36kmh
−1
Since its acceleration = 1.0ms
−2, the time t
1 taken by it to attain the maximum speed is given by

The distance covered by motorcycle in attaining the maximum speed is

The time during which the motorcycle moves with maximum speed is (t − 10)s.
The distance covered by the motorcycle during this time is

∴ Total distance travelled by motorcycle in time t is
For car:Maximum speed attained =

Since its acceleration = 0.5ms
−2 The time taken by it to attain the maximum speed is given by
15 = 0 + 0.5 x t
2 or t
2 = 30s (∵ u = 0)
The distance covered by the car in attaining the maximum speed is

The time during which the car moves with maximum speed is (t − 30)s.
The distance covered by the car during this time is

∴ Total distance travelled by car in time t is

From equations (i) and (ii), we get
10t − 50 = 151 − 225 or 51 = 175 or 1 = 35s
A motorcycle and a car start from rest from the same place at the same...
^2 and the car accelerates at 0.5 m/s^2. After 10 seconds, which vehicle will have traveled further?