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In a cylinder, if the radius is doubled and the height is halved. The curved surface area will be:
- a)Halved
- b)Same
- c)Doubled
- d)Four times
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
In a cylinder, if the radius is doubled and the height is halved. The ...
The curved surface area of a cylinder is given by the formula 2πrh, where r is the radius and h is the height.
If the radius is doubled, the new radius will be 2r. If the height is halved, the new height will be h/2.
Substituting these values in the formula for curved surface area, we get:
New curved surface area = 2π(2r)(h/2) = 2πrh
This is the same as the original curved surface area.
Therefore, the answer is option b) Same.
If the radius is doubled, the new radius will be 2r. If the height is halved, the new height will be h/2.
Substituting these values in the formula for curved surface area, we get:
New curved surface area = 2π(2r)(h/2) = 2πrh
This is the same as the original curved surface area.
Therefore, the answer is option b) Same.
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In a cylinder, if the radius is doubled and the height is halved. The ...
Let's denote the initial radius as r and the initial height as h. The curved surface area (CSA) of a cylinder is given by the formula:
CSA = 2 * pi * r * h
Now, if we double the radius and halve the height, we get a new radius of 2r and a new height of h/2. The new curved surface area (CSA') will be:
CSA' = 2 * pi * (2r) * (h/2)
Now, let's simplify the equation:
CSA' = 2 * pi * 2r * h/2
CSA' = (2 * pi * r * h) * (2/2)
Since 2/2 = 1, we have:
CSA' = 2 * pi * r * h
Comparing the initial curved surface area (CSA) and the new curved surface area (CSA'), we can see that they are equal:
CSA = CSA'
Therefore, the curved surface area remains the same when the radius is doubled and the height is halved.
The correct answer is (b) Same.
CSA = 2 * pi * r * h
Now, if we double the radius and halve the height, we get a new radius of 2r and a new height of h/2. The new curved surface area (CSA') will be:
CSA' = 2 * pi * (2r) * (h/2)
Now, let's simplify the equation:
CSA' = 2 * pi * 2r * h/2
CSA' = (2 * pi * r * h) * (2/2)
Since 2/2 = 1, we have:
CSA' = 2 * pi * r * h
Comparing the initial curved surface area (CSA) and the new curved surface area (CSA'), we can see that they are equal:
CSA = CSA'
Therefore, the curved surface area remains the same when the radius is doubled and the height is halved.
The correct answer is (b) Same.
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In a cylinder, if the radius is doubled and the height is halved. The curved surface area will be:a)Halvedb)Samec)Doubledd)Four timesCorrect answer is option 'B'. Can you explain this answer?
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