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A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).
- a)0
- b)10 m s-1
- c)25 ms-1
- d)50 ms-1
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A ball A is dropped from a building of height 45 m. Simultaneously ano...
Here, uA = −0 , uB = +50ms−1
aA = −g , aB = −g
uBA = uB − uA = 50ms−1 − (0)ms−1 = 50ms−1
aBA = aB − aA = −g − (−g) = 0
∵ vBA = uBA + aBAt(As aBA = 0)
∴ vBA = uBA
As there is no acceleration of ball B w.r.t to ball A, therefore the relative speed of ball B w.r.t ball A at any instant of time remains constant (= 50ms−1).
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Community Answer
A ball A is dropped from a building of height 45 m. Simultaneously ano...
To solve this problem, we need to consider the motion of both balls A and B separately.
For ball A:
Since ball A is dropped, it only experiences free fall due to gravity. The height of the building is 45 m, so the initial velocity of ball A is 0 m/s (since it is dropped) and the final velocity is unknown. The acceleration due to gravity, g, is approximately 9.8 m/s^2. Using the equation of motion:
h = ut + (1/2)gt^2
where h is the height, u is the initial velocity, g is the acceleration due to gravity, and t is the time taken.
Substituting the given values, we have:
45 = 0 + (1/2)(9.8)t^2
Simplifying the equation:
45 = 4.9t^2
Dividing both sides by 4.9:
t^2 = 9.18
Taking the square root of both sides:
t ≈ 3.03 seconds
Therefore, ball A will take approximately 3.03 seconds to reach the ground.
For ball B:
Ball B is thrown up with a speed of 50 m/s. The initial velocity, u, is 50 m/s, and the acceleration due to gravity, g, is still approximately 9.8 m/s^2. Using the equation of motion:
v = u - gt
where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and t is the time taken.
Substituting the given values, we have:
0 = 50 - 9.8t
Simplifying the equation:
9.8t = 50
Dividing both sides by 9.8:
t ≈ 5.1 seconds
Therefore, ball B will take approximately 5.1 seconds to reach its maximum height.
In summary, ball A will take approximately 3.03 seconds to reach the ground, while ball B will take approximately 5.1 seconds to reach its maximum height.
For ball A:
Since ball A is dropped, it only experiences free fall due to gravity. The height of the building is 45 m, so the initial velocity of ball A is 0 m/s (since it is dropped) and the final velocity is unknown. The acceleration due to gravity, g, is approximately 9.8 m/s^2. Using the equation of motion:
h = ut + (1/2)gt^2
where h is the height, u is the initial velocity, g is the acceleration due to gravity, and t is the time taken.
Substituting the given values, we have:
45 = 0 + (1/2)(9.8)t^2
Simplifying the equation:
45 = 4.9t^2
Dividing both sides by 4.9:
t^2 = 9.18
Taking the square root of both sides:
t ≈ 3.03 seconds
Therefore, ball A will take approximately 3.03 seconds to reach the ground.
For ball B:
Ball B is thrown up with a speed of 50 m/s. The initial velocity, u, is 50 m/s, and the acceleration due to gravity, g, is still approximately 9.8 m/s^2. Using the equation of motion:
v = u - gt
where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and t is the time taken.
Substituting the given values, we have:
0 = 50 - 9.8t
Simplifying the equation:
9.8t = 50
Dividing both sides by 9.8:
t ≈ 5.1 seconds
Therefore, ball B will take approximately 5.1 seconds to reach its maximum height.
In summary, ball A will take approximately 3.03 seconds to reach the ground, while ball B will take approximately 5.1 seconds to reach its maximum height.
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A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? for NEET 2026 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer?.
A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? for NEET 2026 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer?.
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