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In an experiment, the period of oscillation of a simple pendulum was observed to be 2.63s, 2.56s, 2.42s, 2.71s and 2.80s. The mean absolute error is
  • a)
    0.11s
  • b)
    0.12s
  • c)
    0.13s
  • d)
    0.14s
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In an experiment, the period of oscillation of a simple pendulum was o...
The mean period of oscillation of the pendulum is

(Rounded off to two decimal places)
The absolute errors in the measurement are
ΔT1 = 2.62s − 2.63s = −0.01s
ΔT2 = 2.62s − 2.56s = 0.06s
ΔT3 = 2.62s − 2.42s = 0.20s
ΔT4 = 2.62s − 2.71s = −0.09s
ΔT5 = 2.62s − 2.80s = −0.18s
Mean absolute error is
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In an experiment, the period of oscillation of a simple pendulum was observed to be 2.63s, 2.56s, 2.42s, 2.71s and 2.80s. The mean absolute error isa)0.11sb)0.12sc)0.13sd)0.14sCorrect answer is option 'A'. Can you explain this answer? for NEET 2026 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In an experiment, the period of oscillation of a simple pendulum was observed to be 2.63s, 2.56s, 2.42s, 2.71s and 2.80s. The mean absolute error isa)0.11sb)0.12sc)0.13sd)0.14sCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment, the period of oscillation of a simple pendulum was observed to be 2.63s, 2.56s, 2.42s, 2.71s and 2.80s. The mean absolute error isa)0.11sb)0.12sc)0.13sd)0.14sCorrect answer is option 'A'. Can you explain this answer?.
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