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Two resistors of resistances R1 = (300 ± 3)Ω and R2 = (500 ± 4)Ω are connected in series. The equivalent resistance of the series combination is
  • a)
    (800 ± 1)Ω
  • b)
    (800 ± 7) Ω
  • c)
    (200 ± 7) Ω
  • d)
    (200 ± 1) Ω
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Two resistors of resistances R1 = (300 ± 3)Ω and R2 = (50...
Calculation of Equivalent Resistance:
The equivalent resistance of resistors in series is simply the sum of the individual resistances.

Given Resistances:
R1 = (300 ± 3)Ω
R2 = (500 ± 4)Ω

Calculating the Total Resistance:
Total resistance (R_total) = R1 + R2
R_total = (300 ± 3)Ω + (500 ± 4)Ω
R_total = (800 ± 7)Ω
Therefore, the equivalent resistance of the series combination is (800 ± 7)Ω.

Conclusion:
The correct answer is option 'B', (800 ± 7)Ω.
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Community Answer
Two resistors of resistances R1 = (300 ± 3)Ω and R2 = (50...
The equivalent resistance of series combination is
Rs = R1 + R= 300Ω + 500Ω = 800Ω
The error in equivalent resistance is given by
ΔR = (ΔR1 + ΔR2) = (3 + 4)Ω = 7Ω
Hence, the equivalent resistance along with error is (800 ± 7)Ω.
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Two resistors of resistances R1 = (300 ± 3)Ω and R2 = (500 ± 4)Ω are connected in series. The equivalent resistance of the series combination isa)(800 ± 1)Ωb)(800 ± 7)Ωc)(200 ± 7)Ωd)(200 ± 1)ΩCorrect answer is option 'B'. Can you explain this answer? for NEET 2026 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two resistors of resistances R1 = (300 ± 3)Ω and R2 = (500 ± 4)Ω are connected in series. The equivalent resistance of the series combination isa)(800 ± 1)Ωb)(800 ± 7)Ωc)(200 ± 7)Ωd)(200 ± 1)ΩCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two resistors of resistances R1 = (300 ± 3)Ω and R2 = (500 ± 4)Ω are connected in series. The equivalent resistance of the series combination isa)(800 ± 1)Ωb)(800 ± 7)Ωc)(200 ± 7)Ωd)(200 ± 1)ΩCorrect answer is option 'B'. Can you explain this answer?.
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