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If g is the accleration due to gravity on earth surface, the gain in potential energy of an object of mass m raised from the surface of earth to a height equal to radius of earth R will be a)1/2 mgR b)2 mgR c)mgR d)1/4 mgR
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If g is the accleration due to gravity on earth surface, the gain in p...
At earth surface, P.E. of system is –GmM/R At a distance R from the earth’s surface, P.E. of system is – GmM/2R? ? U = - GmM / 2R + GmM/R ; ?U = GmM /2RNow GM/R2 = g; ?GM / R = gR ? ?U = ½ mgR therefore answer is 1/2mgR
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If g is the accleration due to gravity on earth surface, the gain in p...
Answer:
To calculate the gain in potential energy (PE) of an object raised from the surface of the Earth to a height equal to the radius of the Earth (R), we can use the formula for potential energy:
PE = mgh
Where:
PE = Potential Energy
m = Mass of the object
g = Acceleration due to gravity
h = Height
In this case, we need to find the potential energy when the object is raised to a height equal to the radius of the Earth. So, h = R.
Therefore, the formula becomes:
PE = m*g*R
Now we need to calculate the gain in potential energy, which is the difference in potential energy between the initial and final positions.
The initial position is at the surface of the Earth, so the potential energy at the surface is:
PE_initial = m*g*0 = 0
The final position is at a height equal to the radius of the Earth, so the potential energy at this height is:
PE_final = m*g*R
The gain in potential energy is therefore:
Gain in PE = PE_final - PE_initial
= m*g*R - 0
= m*g*R
Therefore, the gain in potential energy of an object of mass m raised from the surface of the Earth to a height equal to the radius of the Earth (R) is mgR.
So, the correct answer is option c) mgR.
To calculate the gain in potential energy (PE) of an object raised from the surface of the Earth to a height equal to the radius of the Earth (R), we can use the formula for potential energy:
PE = mgh
Where:
PE = Potential Energy
m = Mass of the object
g = Acceleration due to gravity
h = Height
In this case, we need to find the potential energy when the object is raised to a height equal to the radius of the Earth. So, h = R.
Therefore, the formula becomes:
PE = m*g*R
Now we need to calculate the gain in potential energy, which is the difference in potential energy between the initial and final positions.
The initial position is at the surface of the Earth, so the potential energy at the surface is:
PE_initial = m*g*0 = 0
The final position is at a height equal to the radius of the Earth, so the potential energy at this height is:
PE_final = m*g*R
The gain in potential energy is therefore:
Gain in PE = PE_final - PE_initial
= m*g*R - 0
= m*g*R
Therefore, the gain in potential energy of an object of mass m raised from the surface of the Earth to a height equal to the radius of the Earth (R) is mgR.
So, the correct answer is option c) mgR.
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If g is the accleration due to gravity on earth surface, the gain in potential energy of an object of mass m raised from the surface of earth to a height equal to radius of earth R will be a)1/2 mgR b)2 mgR c)mgR d)1/4 mgR
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If g is the accleration due to gravity on earth surface, the gain in potential energy of an object of mass m raised from the surface of earth to a height equal to radius of earth R will be a)1/2 mgR b)2 mgR c)mgR d)1/4 mgR for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about If g is the accleration due to gravity on earth surface, the gain in potential energy of an object of mass m raised from the surface of earth to a height equal to radius of earth R will be a)1/2 mgR b)2 mgR c)mgR d)1/4 mgR covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If g is the accleration due to gravity on earth surface, the gain in potential energy of an object of mass m raised from the surface of earth to a height equal to radius of earth R will be a)1/2 mgR b)2 mgR c)mgR d)1/4 mgR.
If g is the accleration due to gravity on earth surface, the gain in potential energy of an object of mass m raised from the surface of earth to a height equal to radius of earth R will be a)1/2 mgR b)2 mgR c)mgR d)1/4 mgR for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about If g is the accleration due to gravity on earth surface, the gain in potential energy of an object of mass m raised from the surface of earth to a height equal to radius of earth R will be a)1/2 mgR b)2 mgR c)mgR d)1/4 mgR covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If g is the accleration due to gravity on earth surface, the gain in potential energy of an object of mass m raised from the surface of earth to a height equal to radius of earth R will be a)1/2 mgR b)2 mgR c)mgR d)1/4 mgR.
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