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For an orthorhombic crystal a=450ppm,b=650,c=400,what is the interplanar distance for ,(1,1,0)?
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For an orthorhombic crystal a=450ppm,b=650,c=400,what is the interplan...
Interplanar Distance Calculation for Orthorhombic Crystal


Given:


  • a = 450 ppm

  • b = 650 ppm

  • c = 400

  • Miller indices (hkl) = (1 1 0)



Step 1: Convert ppm to Angstroms


ppm stands for parts per million and is used to express the relative change in length for each crystal axis. To calculate the length in Angstroms, we use the following formula:


Length in Angstroms = L0 * (1 + ppm/10^6)


where L0 is the original length of the crystal axis. For this problem, we have:



  • a = 450 ppm = 0.045%

  • b = 650 ppm = 0.065%

  • c = 400



Using the formula above, we get:



  • a = 450 * 10^-4 * 5.645 = 0.254 Å

  • b = 650 * 10^-4 * 6.45 = 0.419 Å

  • c = 400 Å



Step 2: Calculate the Interplanar Distance


The interplanar distance (d) is given by the following formula:


d = 1 / sqrt((h^2/a^2) + (k^2/b^2) + (l^2/c^2))


where h, k, and l are the Miller indices. For this problem, we have:



  • h = 1

  • k = 1

  • l = 0

  • a = 0.254 Å

  • b = 0.419 Å

  • c = 400 Å



Substituting these values in the formula above, we get:


d = 1 / sqrt((1^2/0.254^2) + (1^2/0.419^2) + (0^2/400^2)) = 0.229 Å


Step 3: Interpretation


The interplanar distance for the (1 1 0) plane in the given orthorhombic crystal is 0.229 Å. This value represents the spacing between adjacent (1 1 0) planes in the crystal lattice. The smaller the interplanar distance, the more closely spaced the planes are and the more tightly packed the crystal lattice is. The interplanar distance is an important parameter in crystallography as it provides information about the crystal structure and properties.
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For an orthorhombic crystal a=450ppm,b=650,c=400,what is the interplanar distance for ,(1,1,0)?
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