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If a mixture of milk and water contains milk and water in the ratio 7:2, as mixture contains milk and water in the ratio 5:3, in what ratio should the two mixtures be mixed so that the ratio of water & milk becomes 3:7?
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If a mixture of milk and water contains milk and water in the ratio 7:...
Let's assume that we have x units of the first mixture and y units of the second mixture.

According to the problem, the first mixture has milk and water in the ratio 7:2. This means that out of every 9 units of the mixture, 7 units are milk and 2 units are water. Therefore, the amount of milk in x units of the first mixture is (7/9)x and the amount of water is (2/9)x.

Similarly, the second mixture has milk and water in the ratio 5:3. This means that out of every 8 units of the mixture, 5 units are milk and 3 units are water. Therefore, the amount of milk in y units of the second mixture is (5/8)y and the amount of water is (3/8)y.

When these two mixtures are combined, the total amount of milk is (7/9)x + (5/8)y and the total amount of water is (2/9)x + (3/8)y.

We want to find the ratio of water to milk in the final mixture. This is given by:

(2/9)x + (3/8)y : (7/9)x + (5/8)y

To simplify this expression, we can cross-multiply:

(2/9)x + (3/8)y = k(7/9)x + k(5/8)y

where k is the ratio in which the two mixtures are mixed.

Simplifying this equation, we get:

(2/9)x - k(7/9)x = k(5/8)y - (3/8)y

(2-7k)/9 x = (5k-3)/8 y

We can now solve for k:

k = [(5/8)y - (3/8)y]/[(2/9)x - (7/9)x]

k = (2/9)y / (-5/9)x

k = -2/5

Therefore, the two mixtures should be mixed in the ratio 2:3 (or 2 parts of the first mixture to 3 parts of the second mixture) so that the ratio of water to milk in the final mixture is 3:7.
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