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Air enters an insulted diffuser operating at steady state with pressure of 1bar and temperature of 300k, with a velocity of 250m/s . at the exit the pressure is 1.13bar velocity is 140m/s Neglecting the change in potential energy and assuming the gas is ideal, find the exit temperature and ratio of exit flow area to input flow area.?
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Air enters an insulted diffuser operating at steady state with pressur...
Given:
- Air enters an insulated diffuser operating at steady state
- Inlet conditions:
- Pressure (P1) = 1 bar
- Temperature (T1) = 300 K
- Velocity (V1) = 250 m/s
- Outlet conditions:
- Pressure (P2) = 1.13 bar
- Velocity (V2) = 140 m/s
- Assumptions:
- Neglecting the change in potential energy
- Gas is ideal

To Find:
- Exit temperature (T2)
- Ratio of exit flow area to input flow area (A2/A1)

Solution:

Step 1: Calculate the exit temperature (T2)
We can use the ideal gas equation to calculate the exit temperature:

P1 * V1 / T1 = P2 * V2 / T2

Plugging in the given values:
1 bar * 250 m/s / 300 K = 1.13 bar * 140 m/s / T2

Simplifying the equation:
(1 bar * 250 m/s) / (300 K) = (1.13 bar * 140 m/s) / T2

Cross-multiplying and solving for T2:
T2 = (1.13 bar * 140 m/s * 300 K) / (1 bar * 250 m/s)

T2 = 1.326 K

Therefore, the exit temperature (T2) is 1.326 K.

Step 2: Calculate the ratio of exit flow area to input flow area (A2/A1)
To calculate the ratio of exit flow area to input flow area, we can use the continuity equation, which states that the mass flow rate is constant for an incompressible flow:

A1 * V1 = A2 * V2

Plugging in the given values:
A1 * 250 m/s = A2 * 140 m/s

Simplifying the equation:
A2/A1 = V1 / V2

Substituting the given values:
A2/A1 = 250 m/s / 140 m/s

A2/A1 = 1.79

Therefore, the ratio of exit flow area to input flow area (A2/A1) is 1.79.

Conclusion:
- The exit temperature (T2) is calculated to be 1.326 K.
- The ratio of exit flow area to input flow area (A2/A1) is calculated to be 1.79.
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Air enters an insulted diffuser operating at steady state with pressure of 1bar and temperature of 300k, with a velocity of 250m/s . at the exit the pressure is 1.13bar velocity is 140m/s Neglecting the change in potential energy and assuming the gas is ideal, find the exit temperature and ratio of exit flow area to input flow area.?
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Air enters an insulted diffuser operating at steady state with pressure of 1bar and temperature of 300k, with a velocity of 250m/s . at the exit the pressure is 1.13bar velocity is 140m/s Neglecting the change in potential energy and assuming the gas is ideal, find the exit temperature and ratio of exit flow area to input flow area.? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Air enters an insulted diffuser operating at steady state with pressure of 1bar and temperature of 300k, with a velocity of 250m/s . at the exit the pressure is 1.13bar velocity is 140m/s Neglecting the change in potential energy and assuming the gas is ideal, find the exit temperature and ratio of exit flow area to input flow area.? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Air enters an insulted diffuser operating at steady state with pressure of 1bar and temperature of 300k, with a velocity of 250m/s . at the exit the pressure is 1.13bar velocity is 140m/s Neglecting the change in potential energy and assuming the gas is ideal, find the exit temperature and ratio of exit flow area to input flow area.?.
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