A juggler keeps 5 balls going with one hand, so that at any instant 4 ...
**Juggling Pattern:**
The juggling pattern described in the question states that the juggler keeps 5 balls going with one hand. At any given instant, 4 balls are in the air while one ball remains in the hand. This means that the juggler continuously throws and catches the balls in a specific rhythm to maintain this pattern.
**Time for Each Ball in Hand:**
To calculate the time for which each ball stays in the hand, we need to consider the time it takes for one complete cycle of throwing and catching the balls.
Let's break down the juggling pattern step by step:
1. **Throwing the First Ball:** The juggler starts by throwing the first ball from their hand, which takes some time. Let's assume this time as 't'.
2. **Throwing the Second Ball:** As soon as the first ball is thrown, the juggler quickly throws the second ball. This requires minimal time as it is a quick motion.
3. **Throwing the Third Ball:** The juggler then throws the third ball, again requiring minimal time.
4. **Throwing the Fourth Ball:** The fourth ball is thrown, similar to the previous two throws.
5. **Catching the First Ball:** After throwing the fourth ball, the juggler catches the first ball that was thrown. This also takes some time, assumed as 't'.
6. **Throwing the Fifth Ball:** As the first ball is caught, the juggler immediately throws the fifth ball.
7. **Catching the Second Ball:** The juggler then catches the second ball, which requires time 't'.
8. **Catching the Third Ball:** The third ball is caught, again requiring time 't'.
9. **Catching the Fourth Ball:** The fourth ball is caught, similar to the previous two catches.
10. **Catching the Fifth Ball:** Finally, the juggler catches the fifth ball, completing the cycle.
**Total Time for Each Cycle:**
In one complete cycle, the juggler throws and catches all five balls. The time taken for each throw and catch is 't', and there are a total of 5 throws and 5 catches in a cycle.
Therefore, the total time for each cycle is 10t (5 throws + 5 catches).
**Time for Each Ball in Hand:**
Since there are 4 balls in the air at any given instant, only one ball remains in the hand. Therefore, the time for which each ball stays in the hand is one-fourth of the total time for each cycle.
Hence, the time for each ball in the hand is (10t)/4 = 2.5t.
Therefore, each ball stays in the hand for a time of 2.5t.
A juggler keeps 5 balls going with one hand, so that at any instant 4 ...
Yes, are wright, ans. is 1s.explanation- assume that man has thrown his first ball. now it will again come back in 4 s. before this he has to catch 4 other balls. hence in 4 s he has to catch 4 balls. hence time period for each ball in hand is 4/4 = 1 s.
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.