Which one of the followings has maximum number of atoms? (2020)a)1g ...
(a) no. of atoms

(b) no. of atoms

(c) no. of atoms

(d) no. of atoms

∴ 1 gm of Li is having maximum no. of atoms.
View all questions of this testWhich one of the followings has maximum number of atoms? (2020)a)1g ...
Maximum number of atoms
Explanation:
The number of atoms in a substance depends on its atomic mass and Avogadro's number. Avogadro's number is the number of atoms in one mole of a substance, which is approximately 6.022 x 10^23.
To find the number of atoms in a given amount of substance, we need to convert the mass of the substance to moles using its atomic mass and then multiply by Avogadro's number.
Calculations:
a) 1g of O2(g)
Atomic mass of O = 16
Molar mass of O2 = (2 x 16) = 32 g/mol
Number of moles in 1g of O2 = 1/32 = 0.03125 mol
Number of atoms in 1g of O2 = 0.03125 x 6.022 x 10^23 = 1.88 x 10^22 atoms
b) 1g of Li(s)
Atomic mass of Li = 7
Molar mass of Li = 7 g/mol
Number of moles in 1g of Li = 1/7 = 0.1429 mol
Number of atoms in 1g of Li = 0.1429 x 6.022 x 10^23 = 8.61 x 10^22 atoms
c) 1g of Ag(s)
Atomic mass of Ag = 108
Molar mass of Ag = 108 g/mol
Number of moles in 1g of Ag = 1/108 = 0.009259 mol
Number of atoms in 1g of Ag = 0.009259 x 6.022 x 10^23 = 5.56 x 10^21 atoms
d) 1g of Mg(s)
Atomic mass of Mg = 24
Molar mass of Mg = 24 g/mol
Number of moles in 1g of Mg = 1/24 = 0.04167 mol
Number of atoms in 1g of Mg = 0.04167 x 6.022 x 10^23 = 2.51 x 10^22 atoms
Conclusion:
Therefore, the substance with the maximum number of atoms is 1g of Li(s) with 8.61 x 10^22 atoms.
Which one of the followings has maximum number of atoms? (2020)a)1g ...
Answer is
1g of Li (s)

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