A hemispherical bowl has radius 5.25 cm. The volume of water it would ...
The volume of a hemispherical bowl can be calculated using the formula:
V = (4/3) * π * r^3
where r is the radius of the sphere.
Plugging in the values for r = 5.25 cm, we get:
V = (4/3) * π * (5.25)^3
V = 303.1875 cm^3
Therefore, the correct answer is option B: 303.1875 cm3
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A hemispherical bowl has radius 5.25 cm. The volume of water it would ...
To find the volume of water that a hemispherical bowl can contain, we can use the formula for the volume of a hemisphere, which is (2/3)πr³.
Given that the radius of the bowl is 5.25 cm, we can substitute this value into the formula to find the volume.
Calculations:
Volume of hemisphere = (2/3)πr³
= (2/3)π(5.25)³
= (2/3)π(5.25)(5.25)(5.25)
≈ 303.1875 cm³
Therefore, the volume of water that the hemispherical bowl can contain is approximately 303.1875 cm³.
Explanation:
A hemispherical bowl is a bowl shaped like half of a sphere. The radius of the bowl is given as 5.25 cm.
To find the volume of the bowl, we can use the formula for the volume of a hemisphere, which is (2/3)πr³.
In this formula, "r" represents the radius of the hemisphere. By substituting the given value for the radius (5.25 cm) into the formula, we can calculate the volume.
After performing the calculations, we find that the volume of water that the hemispherical bowl can contain is approximately 303.1875 cm³.
Therefore, the correct answer is option B, 303.1875 cm³.
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