Civil Engineering (CE) Exam > Civil Engineering (CE) Questions > For medium silt whose average grain size is 0...
Start Learning for Free
For medium silt whose average grain size is 0.16 mm, Lacey’s silt factor is likely to be
- a)0.30
- b)0.45
- c)0.70
- d)1.32
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
For medium silt whose average grain size is 0.16 mm, Laceys silt facto...
Introduction:
In soil mechanics, the silt factor is a parameter used to characterize the grain size distribution of silt. It is denoted by the symbol "F" and is calculated using Laceys equation. The silt factor is an important parameter in geotechnical engineering as it helps in determining the properties and behavior of silt soils.
Laceys equation:
Laceys equation is used to calculate the silt factor for silt soils. It is given by the equation:
F = D30 / D50
Where:
- F is the silt factor
- D30 is the grain size for which 30% of the soil particles are finer (in millimeters)
- D50 is the grain size for which 50% of the soil particles are finer (in millimeters)
Calculating the silt factor:
Given that the average grain size of the medium silt is 0.16 mm, we need to calculate the values of D30 and D50 to determine the silt factor.
Step 1: Calculate D30
D30 is the grain size for which 30% of the soil particles are finer. To calculate D30, we can use the following formula:
D30 = D50 * (F/0.45)^m
Where:
- F is the silt factor (unknown)
- D50 is the grain size for which 50% of the soil particles are finer (unknown)
- m is a constant (0.91 for silt)
Step 2: Calculate D50
D50 is the grain size for which 50% of the soil particles are finer. Given that the average grain size is 0.16 mm, we can assume that D50 is equal to the average grain size for this case.
D50 = 0.16 mm
Step 3: Substitute values into the equation
Substituting the values of D50 and m into the equation from Step 1, we can solve for F:
D30 = 0.16 * (F/0.45)^0.91
Simplifying the equation, we have:
(F/0.45)^0.91 = D30 / 0.16
Taking the natural logarithm of both sides, we get:
0.91 * ln(F/0.45) = ln(D30/0.16)
Solving for F, we have:
F/0.45 = e^(ln(D30/0.16)/0.91)
F = 0.45 * e^(ln(D30/0.16)/0.91)
Step 4: Substitute D30 and calculate F
Given that the average grain size is 0.16 mm and we are dealing with medium silt, we can assume that D30 is approximately 0.09 mm. Substituting this value into the equation, we can calculate F:
F = 0.45 * e^(ln(0.09/0.16)/0.91)
F ≈ 0.70
Therefore, the silt factor for medium silt with an average grain size of 0.16 mm is approximately 0.70.
In soil mechanics, the silt factor is a parameter used to characterize the grain size distribution of silt. It is denoted by the symbol "F" and is calculated using Laceys equation. The silt factor is an important parameter in geotechnical engineering as it helps in determining the properties and behavior of silt soils.
Laceys equation:
Laceys equation is used to calculate the silt factor for silt soils. It is given by the equation:
F = D30 / D50
Where:
- F is the silt factor
- D30 is the grain size for which 30% of the soil particles are finer (in millimeters)
- D50 is the grain size for which 50% of the soil particles are finer (in millimeters)
Calculating the silt factor:
Given that the average grain size of the medium silt is 0.16 mm, we need to calculate the values of D30 and D50 to determine the silt factor.
Step 1: Calculate D30
D30 is the grain size for which 30% of the soil particles are finer. To calculate D30, we can use the following formula:
D30 = D50 * (F/0.45)^m
Where:
- F is the silt factor (unknown)
- D50 is the grain size for which 50% of the soil particles are finer (unknown)
- m is a constant (0.91 for silt)
Step 2: Calculate D50
D50 is the grain size for which 50% of the soil particles are finer. Given that the average grain size is 0.16 mm, we can assume that D50 is equal to the average grain size for this case.
D50 = 0.16 mm
Step 3: Substitute values into the equation
Substituting the values of D50 and m into the equation from Step 1, we can solve for F:
D30 = 0.16 * (F/0.45)^0.91
Simplifying the equation, we have:
(F/0.45)^0.91 = D30 / 0.16
Taking the natural logarithm of both sides, we get:
0.91 * ln(F/0.45) = ln(D30/0.16)
Solving for F, we have:
F/0.45 = e^(ln(D30/0.16)/0.91)
F = 0.45 * e^(ln(D30/0.16)/0.91)
Step 4: Substitute D30 and calculate F
Given that the average grain size is 0.16 mm and we are dealing with medium silt, we can assume that D30 is approximately 0.09 mm. Substituting this value into the equation, we can calculate F:
F = 0.45 * e^(ln(0.09/0.16)/0.91)
F ≈ 0.70
Therefore, the silt factor for medium silt with an average grain size of 0.16 mm is approximately 0.70.
Attention Civil Engineering (CE) Students!
To make sure you are not studying endlessly, EduRev has designed Civil Engineering (CE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Civil Engineering (CE).
|
Explore Courses for Civil Engineering (CE) exam
|
|
Similar Civil Engineering (CE) Doubts
Top Courses for Civil Engineering (CE)View all
For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer?
Question Description
For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer?.
For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer?.
Solutions for For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Here you can find the meaning of For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer?, a detailed solution for For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice For medium silt whose average grain size is 0.16 mm, Laceys silt factor is likely to bea)0.30b)0.45c)0.70d)1.32Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
|
|
Explore Courses for Civil Engineering (CE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup