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A s h m is given by x = 6 cos (100t π/4) . where x is in cm and t is in second .what is the displacement of amplitude and frequency?
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A s h m is given by x = 6 cos (100t π/4) . where x is in cm and t is...
Displacement and Amplitude in SHM

Simple Harmonic Motion (SHM) is a type of motion where the restoring force is proportional to the displacement from equilibrium. The displacement of an object undergoing SHM can be described using the following equation:

x = A cos(ωt + φ)


Amplitude

The amplitude of an object undergoing SHM is the maximum displacement from equilibrium. In the given equation, x = 6 cos (100t π/4), the amplitude is 6 cm. This means that the object oscillates between a maximum displacement of +6 cm and -6 cm.


Frequency

The frequency of an object undergoing SHM is the number of complete oscillations per unit time. The angular frequency (ω) is equal to 2π times the frequency (f). In the given equation, x = 6 cos (100t π/4), the angular frequency is 100π/4 radians per second. This means that the frequency is:

f = (ω/2π) = (100π/4)/(2π) = 25 Hz

Therefore, the object undergoes 25 complete oscillations per second.
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A s h m is given by x = 6 cos (100t π/4) . where x is in cm and t is in second .what is the displacement of amplitude and frequency?
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A s h m is given by x = 6 cos (100t π/4) . where x is in cm and t is in second .what is the displacement of amplitude and frequency? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A s h m is given by x = 6 cos (100t π/4) . where x is in cm and t is in second .what is the displacement of amplitude and frequency? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A s h m is given by x = 6 cos (100t π/4) . where x is in cm and t is in second .what is the displacement of amplitude and frequency?.
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