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5 coins are tossed 128 times. What is the probability of getting 3 Or more heads and find out the expected Frequencies of 3 or more heads?
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5 coins are tossed 128 times. What is the probability of getting 3 Or ...
Probability of getting 3 or more heads out of 5 coins tossed 128 times

To find the probability of getting 3 or more heads out of 5 coins tossed 128 times, we can use the binomial distribution formula.

P(X ≥ 3) = 1 - P(X < />

Where X is the number of heads obtained in a single toss of 5 coins and P is the probability of getting X heads.

The probability of getting X heads in a single toss of 5 coins is given by the formula:

P(X) = (nCx) * p^x * q^(n-x)

Where n is the number of trials (128 in this case), p is the probability of success in a single trial (0.5 for getting heads), q is the probability of failure (0.5 for getting tails), and nCx is the binomial coefficient.

Using this formula, we can calculate the probabilities of getting 0, 1, and 2 heads in a single toss of 5 coins.

P(X = 0) = (5C0) * 0.5^0 * 0.5^5 = 0.03125
P(X = 1) = (5C1) * 0.5^1 * 0.5^4 = 0.15625
P(X = 2) = (5C2) * 0.5^2 * 0.5^3 = 0.3125

Now, we can use the formula for P(X ≥ 3) to find the probability of getting 3 or more heads:

P(X ≥ 3) = 1 - P(X < />
P(X ≥ 3) = 1 - (P(X = 0) + P(X = 1) + P(X = 2))
P(X ≥ 3) = 1 - (0.03125 + 0.15625 + 0.3125)
P(X ≥ 3) = 0.5

Therefore, the probability of getting 3 or more heads out of 5 coins tossed 128 times is 0.5 or 50%.

Expected frequencies of 3 or more heads

To find the expected frequencies of 3 or more heads, we can multiply the probability of getting 3 or more heads by the total number of tosses (128):

Expected frequency = Probability * Total number of tosses

Expected frequency = 0.5 * 128
Expected frequency = 64

Therefore, we can expect to get 3 or more heads in about 64 out of 128 tosses.
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5 coins are tossed 128 times. What is the probability of getting 3 Or more heads and find out the expected Frequencies of 3 or more heads?
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