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In this question. A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at a constant speed of 4 ms −1 . The tension in the string is 6 N when the stone is Why is the tension in the string not zero at top point because minimum value needed of velocity at lowest point for reaching top/successful rotation is √5gR which is 7 m/sec?
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In this question. A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at a constant speed of 4 ms −1 . The tension in the string is 6 N when the stone is Why is the tension in the string not zero at top point because minimum value needed of velocity at lowest point for reaching top/successful rotation is √5gR which is 7 m/sec?
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In this question. A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at a constant speed of 4 ms −1 . The tension in the string is 6 N when the stone is Why is the tension in the string not zero at top point because minimum value needed of velocity at lowest point for reaching top/successful rotation is √5gR which is 7 m/sec? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In this question. A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at a constant speed of 4 ms −1 . The tension in the string is 6 N when the stone is Why is the tension in the string not zero at top point because minimum value needed of velocity at lowest point for reaching top/successful rotation is √5gR which is 7 m/sec? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In this question. A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at a constant speed of 4 ms −1 . The tension in the string is 6 N when the stone is Why is the tension in the string not zero at top point because minimum value needed of velocity at lowest point for reaching top/successful rotation is √5gR which is 7 m/sec?.
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