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Anil went 15 kms to the west from my house, then turned left and walked 20 kms. He then turned East and walked 25 kms and finally turning left covered 20 kms. How far was he from his house?
- a)5 kms
- b)10 kms
- c)40 kms
- d)80 kms
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Anil went 15 kms to the west from my house, then turned left and walke...
Anil's movements can be visualized as follows:
1. Heading West: Anil goes 15 km to the west from the starting point.
2. Turning Left: Anil turns left and walks 20 km.
3. Heading East: Anil turns east and walks 25 km.
4. Turning Left: Anil turns left again and walks 20 km.
To calculate Anil's distance from his starting point, we can break down his movements into two perpendicular directions: North-South and East-West.
North-South Direction:
- Anil's initial movement to the west does not affect his position in the North-South direction.
- Anil's subsequent movements (20 km to the left and 20 km to the right) cancel each other out, resulting in no net displacement in the North-South direction.
East-West Direction:
- Anil's initial movement of 15 km to the west gives a displacement of -15 km in the East-West direction.
- Anil's subsequent movement of 25 km to the east gives a displacement of +25 km in the East-West direction.
- Anil's final movement of 20 km to the left gives a displacement of -20 km in the East-West direction.
To find the total displacement in the East-West direction, we need to sum up the individual displacements: -15 km + 25 km - 20 km = -10 km.
Now, we can use the Pythagorean theorem to find the distance between Anil's final position and his starting point. The theorem states that the square of the hypotenuse (distance) is equal to the sum of the squares of the other two sides (displacements).
In this case, the displacement in the North-South direction is 0 km, so we only need to consider the displacement in the East-West direction.
Distance = √(displacement in East-West direction)^2 + (displacement in North-South direction)^2
= √((-10 km)^2 + (0 km)^2)
= √(100 km^2)
= 10 km
Therefore, Anil is 10 km away from his starting point. Hence, the correct answer is option 'B' (10 kms).
1. Heading West: Anil goes 15 km to the west from the starting point.
2. Turning Left: Anil turns left and walks 20 km.
3. Heading East: Anil turns east and walks 25 km.
4. Turning Left: Anil turns left again and walks 20 km.
To calculate Anil's distance from his starting point, we can break down his movements into two perpendicular directions: North-South and East-West.
North-South Direction:
- Anil's initial movement to the west does not affect his position in the North-South direction.
- Anil's subsequent movements (20 km to the left and 20 km to the right) cancel each other out, resulting in no net displacement in the North-South direction.
East-West Direction:
- Anil's initial movement of 15 km to the west gives a displacement of -15 km in the East-West direction.
- Anil's subsequent movement of 25 km to the east gives a displacement of +25 km in the East-West direction.
- Anil's final movement of 20 km to the left gives a displacement of -20 km in the East-West direction.
To find the total displacement in the East-West direction, we need to sum up the individual displacements: -15 km + 25 km - 20 km = -10 km.
Now, we can use the Pythagorean theorem to find the distance between Anil's final position and his starting point. The theorem states that the square of the hypotenuse (distance) is equal to the sum of the squares of the other two sides (displacements).
In this case, the displacement in the North-South direction is 0 km, so we only need to consider the displacement in the East-West direction.
Distance = √(displacement in East-West direction)^2 + (displacement in North-South direction)^2
= √((-10 km)^2 + (0 km)^2)
= √(100 km^2)
= 10 km
Therefore, Anil is 10 km away from his starting point. Hence, the correct answer is option 'B' (10 kms).
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Anil went 15 kms to the west from my house, then turned left and walke...
The correct answer is B
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Anil went 15 kms to the west from my house, then turned left and walked 20 kms. He then turned East and walked 25 kms and finally turning left covered 20 kms. How far was he from his house?a)5 kmsb)10 kmsc)40 kmsd)80 kmsCorrect answer is option 'B'. Can you explain this answer?
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Anil went 15 kms to the west from my house, then turned left and walked 20 kms. He then turned East and walked 25 kms and finally turning left covered 20 kms. How far was he from his house?a)5 kmsb)10 kmsc)40 kmsd)80 kmsCorrect answer is option 'B'. Can you explain this answer? for Class 5 2024 is part of Class 5 preparation. The Question and answers have been prepared according to the Class 5 exam syllabus. Information about Anil went 15 kms to the west from my house, then turned left and walked 20 kms. He then turned East and walked 25 kms and finally turning left covered 20 kms. How far was he from his house?a)5 kmsb)10 kmsc)40 kmsd)80 kmsCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 5 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Anil went 15 kms to the west from my house, then turned left and walked 20 kms. He then turned East and walked 25 kms and finally turning left covered 20 kms. How far was he from his house?a)5 kmsb)10 kmsc)40 kmsd)80 kmsCorrect answer is option 'B'. Can you explain this answer?.
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