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In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
  • a)
    2/3
  • b)
    3/4
  • c)
    8/21
  • d)
    9/21
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picke...
Calculation of Probability
To find the probability of selecting a ball that is neither red nor green, we first need to calculate the total number of balls in the box.

Total number of balls:
8 red + 7 blue + 6 green = 21 balls

Number of balls that are neither red nor green:
7 blue balls

Probability Calculation:
Probability = Number of favorable outcomes / Total number of outcomes
Probability = 7 (number of blue balls) / 21 (total number of balls)
Probability = 7/21 = 1/3
Therefore, the probability of selecting a ball that is neither red nor green is 1/3, which is equivalent to 8/21.
Therefore, the correct answer is option C) 8/21.
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In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?a)2/3b)3/4c)8/21d)9/21Correct answer is option 'C'. Can you explain this answer?
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