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A man travels a distance of 2 m towards East, 6 m towards South and finally 6m towards the East. The resultant displacement is
- a)10 m
- b)8 m
- c)12 m
- d)14 m
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A man travels a distance of 2 m towards East, 6 m towards South and f...
Given:
Distance towards East = 2 m
Distance towards South = 6 m
Distance towards East = 6 m
To find: Resultant displacement
Solution:
We can use Pythagoras theorem to find the resultant displacement.
Let's draw a rough diagram:
|<---2m-->|
| |
| |6m
| |
6m |<---6m-->|
| |
| |
| |
From the diagram, we can see that the distance travelled towards East and West cancel each other out.
So, the net displacement in the East direction = 6 m - 2 m = 4 m towards East.
The net displacement in the South direction = 6 m towards South.
Now, we can use Pythagoras theorem to find the resultant displacement:
Resultant displacement = √(East^2 + South^2)
Resultant displacement = √(4^2 + 6^2)
Resultant displacement = √52
Resultant displacement = 7.2 m (approx)
Therefore, the correct option is A) 10m.
Note: The options given in the question are not accurate. The correct answer is approximately 7.2 m.
Distance towards East = 2 m
Distance towards South = 6 m
Distance towards East = 6 m
To find: Resultant displacement
Solution:
We can use Pythagoras theorem to find the resultant displacement.
Let's draw a rough diagram:
|<---2m-->|
| |
| |6m
| |
6m |<---6m-->|
| |
| |
| |
From the diagram, we can see that the distance travelled towards East and West cancel each other out.
So, the net displacement in the East direction = 6 m - 2 m = 4 m towards East.
The net displacement in the South direction = 6 m towards South.
Now, we can use Pythagoras theorem to find the resultant displacement:
Resultant displacement = √(East^2 + South^2)
Resultant displacement = √(4^2 + 6^2)
Resultant displacement = √52
Resultant displacement = 7.2 m (approx)
Therefore, the correct option is A) 10m.
Note: The options given in the question are not accurate. The correct answer is approximately 7.2 m.
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Community Answer
A man travels a distance of 2 m towards East, 6 m towards South and f...
A man starts from O and reaches Q. Shortest distance is OQ.
Apply Pythagoras theorem to
∆ORQ.
(RQ = PM) and (PR = MQ)()
OQ2= OR2+ RQ2
OQ=√{(2+6)2+62}
OQ=10m
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A man travels a distance of 2 m towards East, 6 m towards South and finally 6m towards the East. The resultant displacement isa)10 mb)8 mc)12 md)14 mCorrect answer is option 'A'. Can you explain this answer?
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