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A man travels a distance of 2 m towards East, 6 m towards South and finally 6m towards the East. The resultant displacement is
  • a)
    10 m
  • b)
    8 m
  • c)
    12 m
  • d)
    14 m
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A man travels a distance of 2 m towards East, 6 m towards South and f...
Given:
Distance towards East = 2 m
Distance towards South = 6 m
Distance towards East = 6 m

To find: Resultant displacement

Solution:
We can use Pythagoras theorem to find the resultant displacement.

Let's draw a rough diagram:

|<---2m-->|
| |
| |6m
| |
6m |<---6m-->|
| |
| |
| |

From the diagram, we can see that the distance travelled towards East and West cancel each other out.

So, the net displacement in the East direction = 6 m - 2 m = 4 m towards East.

The net displacement in the South direction = 6 m towards South.

Now, we can use Pythagoras theorem to find the resultant displacement:

Resultant displacement = √(East^2 + South^2)

Resultant displacement = √(4^2 + 6^2)

Resultant displacement = √52

Resultant displacement = 7.2 m (approx)

Therefore, the correct option is A) 10m.

Note: The options given in the question are not accurate. The correct answer is approximately 7.2 m.
Free Test
Community Answer
A man travels a distance of 2 m towards East, 6 m towards South and f...
A man starts from O and reaches Q. Shortest distance is OQ.
Apply Pythagoras theorem to
∆ORQ.
(RQ = PM) and (PR = MQ)()
OQ2= OR2+ RQ2
OQ=√{(2+6)2+62}
OQ=10m
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A man travels a distance of 2 m towards East, 6 m towards South and finally 6m towards the East. The resultant displacement isa)10 mb)8 mc)12 md)14 mCorrect answer is option 'A'. Can you explain this answer?
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