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A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg.
What is the recoil velocity of the pistol?
  • a)
    – 1.25 ms–1
  • b)
    – 1.5 ms–1
  • c)
    1.5 ms–1
  • d)
    2.5 ms–1
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A bullet of mass 20 g is horizontally fired with a velocity of 150 ms...
M1 = 20 g = 0.02 kg, m2 = 2 kg.
u1 = 0, u2 = 0 (both pistol and bullet are at rest)
v1 = + 150 ms–1 (the find velocity of the bullet)
let v2 be the recoil velocity of the pistol
according to the law of conservation, total
moment remains the same.
m1u1 + m2u2 = m1v1 + m2v2
.02 × 0 + 2 × 0 = 0.02 × 150 + 2 × v2
0 = 3 + 2v2
⇒ v2 = -3/2 = – 1.5 ms–1
Negative sign indicates that the pistol will recoil in the opposite direction of the bullet.
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A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg.What is the recoil velocity of the pistol?a)– 1.25 ms–1b)– 1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer?
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