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The momentum of a bullet of mass 20 g fired from a gun is 10 kg. m/s. The kinetic energy of this bulletin kJ will be
  • a)
    5
  • b)
    1.5
  • c)
    2.5
  • d)
    25
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The momentum of a bullet of mass 20 g fired from a gun is 10 kg. m/s....
K.E. = ½ mv2 = p2/2m (m = 20 g = 0.02kg)
= 10×10/2×0.02 = 2500 j = 2.5 kj
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Community Answer
The momentum of a bullet of mass 20 g fired from a gun is 10 kg. m/s....
Understanding Momentum and Kinetic Energy
To solve for the kinetic energy of the bullet, we first need to understand the relationship between momentum and kinetic energy.
Definitions
- Momentum (p): It is defined as the product of mass (m) and velocity (v) of an object.
- Formula: p = m * v
- Kinetic Energy (KE): It is defined as the energy that an object possesses due to its motion.
- Formula: KE = (1/2) * m * v^2
Given Information
- Mass of the bullet (m): 20 g = 0.020 kg (conversion to kg)
- Momentum (p): 10 kg·m/s
Finding Velocity
Using the momentum formula:
- p = m * v
- Rearranging gives us: v = p / m
- Substituting the values:
- v = 10 kg·m/s / 0.020 kg = 500 m/s
Calculating Kinetic Energy
Now that we have the velocity, we can find the kinetic energy:
- KE = (1/2) * m * v^2
- KE = (1/2) * 0.020 kg * (500 m/s)^2
- KE = 0.010 kg * 250000 m²/s²
- KE = 2500 J
Converting to kJ
Since 1 kJ = 1000 J:
- KE = 2500 J = 2.5 kJ
Conclusion
The kinetic energy of the bullet is 2.5 kJ, thus confirming that option 'C' is correct.
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The momentum of a bullet of mass 20 g fired from a gun is 10 kg. m/s. The kinetic energy of this bulletin kJ will bea)5b)1.5c)2.5d)25Correct answer is option 'C'. Can you explain this answer?
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