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Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregaion will show :- 
  • a)
    Higher number of the recombinant types.
  • b)
    Segregation in the expected 9:3:3:1 ratio.
  • c)
    Segregation in 3:1 ratio.
  • d)
    Higher number of the parental types
Correct answer is option 'D'. Can you explain this answer?
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Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregaion will show :-a)Higher number of the recombinant types.b)Segregation in the expected 9:3:3:1 ratio.c)Segregation in 3:1 ratio.d)Higher number of the parental typesCorrect answer is option 'D'. Can you explain this answer?
Question Description
Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregaion will show :-a)Higher number of the recombinant types.b)Segregation in the expected 9:3:3:1 ratio.c)Segregation in 3:1 ratio.d)Higher number of the parental typesCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregaion will show :-a)Higher number of the recombinant types.b)Segregation in the expected 9:3:3:1 ratio.c)Segregation in 3:1 ratio.d)Higher number of the parental typesCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregaion will show :-a)Higher number of the recombinant types.b)Segregation in the expected 9:3:3:1 ratio.c)Segregation in 3:1 ratio.d)Higher number of the parental typesCorrect answer is option 'D'. Can you explain this answer?.
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Here you can find the meaning of Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregaion will show :-a)Higher number of the recombinant types.b)Segregation in the expected 9:3:3:1 ratio.c)Segregation in 3:1 ratio.d)Higher number of the parental typesCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregaion will show :-a)Higher number of the recombinant types.b)Segregation in the expected 9:3:3:1 ratio.c)Segregation in 3:1 ratio.d)Higher number of the parental typesCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregaion will show :-a)Higher number of the recombinant types.b)Segregation in the expected 9:3:3:1 ratio.c)Segregation in 3:1 ratio.d)Higher number of the parental typesCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregaion will show :-a)Higher number of the recombinant types.b)Segregation in the expected 9:3:3:1 ratio.c)Segregation in 3:1 ratio.d)Higher number of the parental typesCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregaion will show :-a)Higher number of the recombinant types.b)Segregation in the expected 9:3:3:1 ratio.c)Segregation in 3:1 ratio.d)Higher number of the parental typesCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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