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Sketch the variation in total stress, effective stress and pore water pressure upto a depth of 6m below ground level, given the following data: The water table is 2m below ground level. The dry unit weight of the soil is 18kN/m3, water content is 12%, specific gravity is 2.65. What would be the change in these stresses if the water table drops by one more meter?
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Sketch the variation in total stress, effective stress and pore water ...
Solution:

Given data:
Water table = 2m below ground level
Dry unit weight of soil (γd) = 18 kN/m3
Water content (w) = 12%
Specific Gravity (Gs) = 2.65

Total stress (σ):
The total stress at any depth (z) below ground level is given by the formula:
σ = γd z
For z < 2m="" (above="" water="" />
σ = 18z
For 2m < z="" />< 6m="" (below="" water="" />
σ = 18(2) + 10(z-2) = 20 + 10z

Effective stress (σ'):
The effective stress at any depth (z) below ground level is given by the formula:
σ' = σ - u
where u is the pore water pressure.
For z < 2m="" (above="" water="" />
u = γw z
where γw is the unit weight of water = 9.81 kN/m3
u = 9.81z
σ' = σ - u = 18z - 9.81z = 8.19z
For 2m < z="" />< 6m="" (below="" water="" />
u = γw (2) + γw (z-2) = 19.62 + 9.81(z-2) = 9.62 + 9.81z
σ' = σ - u = (20 + 10z) - (9.62 + 9.81z) = 10z + 10.38

Pore water pressure (u):
For z < 2m="" (above="" water="" />
u = γw z = 9.81z
For 2m < z="" />< 6m="" (below="" water="" />
u = 19.62 + 9.81(z-2) = 9.62 + 9.81z

Change in stresses if water table drops by one more meter:
If the water table drops by one more meter, then the new water table will be at a depth of 3m below ground level.
Total stress (σ):
For z < 3m="" (above="" water="" />
σ = 18z
For 3m < z="" />< 6m="" (below="" water="" />
σ = 18(3) + 10(z-3) = 24 + 10z

Effective stress (σ'):
For z < 3m="" (above="" water="" />
u = γw z = 9.81z
σ' = σ - u = 18z - 9.81z = 8.19z
For 3m < z="" />< 6m="" (below="" water="" />
u = 19.62 + 9.81(z-3) = 9.81z - 9.62
σ' = σ - u = (24 + 10z) - (9.81z - 9.62) = 14.38 + 0.19z

Pore water pressure (u):
For z < 3m="" (above="" water="" />
u = γw z = 9.81z
For 3m < z="" />< 6m="" (below="" water="" />
u = 19.62 + 9.81(z-3) = 9.81z
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Sketch the variation in total stress, effective stress and pore water pressure upto a depth of 6m below ground level, given the following data: The water table is 2m below ground level. The dry unit weight of the soil is 18kN/m3, water content is 12%, specific gravity is 2.65. What would be the change in these stresses if the water table drops by one more meter?
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Sketch the variation in total stress, effective stress and pore water pressure upto a depth of 6m below ground level, given the following data: The water table is 2m below ground level. The dry unit weight of the soil is 18kN/m3, water content is 12%, specific gravity is 2.65. What would be the change in these stresses if the water table drops by one more meter? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Sketch the variation in total stress, effective stress and pore water pressure upto a depth of 6m below ground level, given the following data: The water table is 2m below ground level. The dry unit weight of the soil is 18kN/m3, water content is 12%, specific gravity is 2.65. What would be the change in these stresses if the water table drops by one more meter? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Sketch the variation in total stress, effective stress and pore water pressure upto a depth of 6m below ground level, given the following data: The water table is 2m below ground level. The dry unit weight of the soil is 18kN/m3, water content is 12%, specific gravity is 2.65. What would be the change in these stresses if the water table drops by one more meter?.
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