The opposite angles of a parallelogram are 2x +10and x+70.find the ang...
**Angles of a Parallelogram**
A parallelogram is a quadrilateral with opposite sides that are parallel and equal in length. The opposite angles of a parallelogram are congruent, meaning they have the same measure.
Let's denote the angles of the parallelogram as follows:
Angle A = 2x - 10
Angle B = 180° - Angle A
Angle C = x + 70
Angle D = 180° - Angle C
To find the angles of the parallelogram, we need to solve the given equations.
**Equation 1: Angle A = 2x - 10**
The first equation gives us the measure of Angle A, which is 2x - 10.
**Equation 2: Angle B = 180° - Angle A**
Angle B is the opposite angle of Angle A, so its measure is also 180° - Angle A.
**Equation 3: Angle C = x + 70**
The third equation gives us the measure of Angle C, which is x + 70.
**Equation 4: Angle D = 180° - Angle C**
Angle D is the opposite angle of Angle C, so its measure is also 180° - Angle C.
To find the values of x and the angles of the parallelogram, we can solve these equations simultaneously.
**Simultaneous Equations:**
1. Angle A = 2x - 10
2. Angle B = 180° - Angle A
3. Angle C = x + 70
4. Angle D = 180° - Angle C
By substituting the values from Equation 1 into Equation 2, we have:
Angle B = 180° - (2x - 10)
Angle B = 180° - 2x + 10
Angle B = 190° - 2x
By substituting the values from Equation 3 into Equation 4, we have:
Angle D = 180° - (x + 70)
Angle D = 180° - x - 70
Angle D = 110° - x
Since the opposite angles of a parallelogram are congruent, we can set Angle B equal to Angle D and solve for x:
190° - 2x = 110° - x
190° - 110° = x - 2x
80° = -x
x = -80°
However, angles cannot have negative measures, so there is no solution for x in this case. Therefore, the given angles, 2x - 10 and x + 70, cannot form the opposite angles of a parallelogram.
In conclusion, the given angles do not represent the angles of a parallelogram.
The opposite angles of a parallelogram are 2x +10and x+70.find the ang...
Opposite angle are equal
2x+10=x+70
X=60
Let the first angle=A
First angle=2x+10
=2×60+10
A =130.
Angle B =108-130(adjacent angle)
Angle C=angle A( Opposite side)
So, angle C=130
Angle B=Angle D (Opposite side)
So, Angle D =50
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