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Hydrolysis of the adduct formed form the reaction of ________ with methyl magnesium bromide gives 2-Methylpropan-2-ol.
  • a)
    Methanal
  • b)
    Ethanal
  • c)
    Propanal
  • d)
    Propanone
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Hydrolysis of the adduct formed form the reaction of ________ with met...
2-Methylpropan-2-ol is a tertiary alcohol which is produced from the hydrolysis of the adduct formed between a ketone and a Grignard reagent.
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Hydrolysis of the adduct formed form the reaction of ________ with met...
Hydrolysis of the adduct formed from the reaction of Propanone with methyl magnesium bromide
Propanone reacts with methyl magnesium bromide (CH3MgBr) to form an adduct. The reaction forms a magnesium alkoxide intermediate, which then reacts with water in the hydrolysis step to give 2-Methylpropan-2-ol.

Reaction:
Propanone + CH3MgBr → Adduct
Adduct + H2O → 2-Methylpropan-2-ol

Explanation:
- Propanone (also known as acetone) reacts with methyl magnesium bromide to form an adduct through a nucleophilic addition reaction.
- The adduct formed is then hydrolyzed by water to give 2-Methylpropan-2-ol.
- The hydrolysis step involves breaking the bond between the carbon and magnesium in the adduct, followed by the addition of a hydroxyl group to one of the carbons to form the alcohol product.
- The final product, 2-Methylpropan-2-ol, is a tertiary alcohol with a branched structure.

Conclusion:
The hydrolysis of the adduct formed from the reaction of Propanone with methyl magnesium bromide results in the formation of 2-Methylpropan-2-ol, a tertiary alcohol. This reaction demonstrates the versatility of organometallic reagents like Grignard reagents in organic synthesis.
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Hydrolysis of the adduct formed form the reaction of ________ with methyl magnesium bromide gives 2-Methylpropan-2-ol.a)Methanalb)Ethanalc)Propanald)PropanoneCorrect answer is option 'D'. Can you explain this answer?
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