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Class 12 Exam  >  Class 12 Questions  >  A metal rod is forced to move with constant v... Start Learning for Free
A metal rod is forced to move with constant velocity along two parallel metal rails, connected with a strip of metal at one end across a magnetic field (B) of 0.5 T, pointing out of the page. The rod is of length 45 cm and the speed of the rod is 70 cm/s. The rod has a resistance of 10 Ω and the resistance of the rails and connector is negligible. What is the rate at which energy is being transferred to thermal energy?
  • a)
    0.225 W
  • b)
    22.55 W
  • c)
    2.25 × 10-4 W
  • d)
    2.25 × 10-3 W
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A metal rod is forced to move with constant velocity along two paralle...
Given: B = 0.5 T; v = 70 cm/s = 70 × 10-2 m/s; L = 45 cm = 45 × 10-2 m; R = 10 Ω
Motional emf (E) = vLB = 70 × 10-2 × 45 × 10-2 × 0.5
E = 0.15 V
Current (I) = E/R
I = 0.15/10
I = 0.015 A
Rate of energy or power (P) = I2R
P = 0.0152 × 10
P = 2.25 × 10-3 W
Therefore, the rate of energy transfer is 2.25 × 10-3 W.
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A metal rod is forced to move with constant velocity along two paralle...
To determine the force exerted on the rod, we can use the formula for the magnetic force on a current-carrying conductor:

F = BIL

Where:
F = force exerted on the rod (in Newtons)
B = magnetic field strength (in Tesla)
I = current flowing through the rod (in Amperes)
L = length of the rod (in meters)

Given:
B = 0.5 T
L = 45 cm = 0.45 m

To find the current flowing through the rod, we can use Ohm's Law:

V = IR

Where:
V = voltage across the rod (in Volts)
I = current flowing through the rod (in Amperes)
R = resistance of the rod (in Ohms)

Given:
R = 10 Ω
V = velocity of the rod = 70 cm/s = 0.7 m/s

Rearranging Ohm's Law, we have:

I = V/R

Substituting the given values, we get:

I = 0.7 m/s / 10 Ω
I = 0.07 A

Now, we can calculate the force exerted on the rod:

F = BIL
F = 0.5 T * 0.07 A * 0.45 m
F = 0.01575 N

Therefore, the force exerted on the rod is approximately 0.01575 Newtons.
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Read the following text and answer the following questions on the basis of the same:Shunt resistance: The ammeter shunt is the device which provides the low resistance path to the flow of current. It is connected in parallel with the ammeter. In some ammeter the shunt is in-built inside the instrument while in others it is externally connected to the circuit. Ammeters are designed for measurement of low current. For measuring high current, the shunt is connected in parallel to the ammeter. The significant portion of the current passes to the shunt because of the low resistance path and little amount of current passes through the ammeter. The shunt is connected in parallel to the ammeter because of which the voltage drops across the meter and shunt remain the same. Thus, the movement of the pointer is not affected by the shunt. Let us consider that the current to be measured is I. The circuit has ammeter and shunt connected parallel to each other. The ammeter is designed for measurement of small current say, Im. The magnitude of the current I passes through the meter is very high, and it will burn the meter. So, for measuring the current I the shunt is required in the circuit. As the shunt connects in parallel with the ammeter, thus the same voltage drops occur between them:IShRSH = ImRm∴ RSH = ImRm/ISHShunt current ISH = I – ImSo, RSH = ImRm/(I – Im)∴ I/Im = 1 + (Rm/RSH)The ratio of the total current to the current required for the movement of the ammeter coil is called the multiplying power of the shunt.∴ The multiplying power = m = I/ImRSH = Rm / (m – 1)The following are the requirements of the shunt.• The resistance of the shunt should remain constant with time.• The temperature of the material should remain the same even though substantial current flows through the circuit.How shunt is connected with a ammeter?

Read the following text and answer the following questions on the basis of the same:Shunt resistance: The ammeter shunt is the device which provides the low resistance path to the flow of current. It is connected in parallel with the ammeter. In some ammeter the shunt is in-built inside the instrument while in others it is externally connected to the circuit. Ammeters are designed for measurement of low current. For measuring high current, the shunt is connected in parallel to the ammeter. The significant portion of the current passes to the shunt because of the low resistance path and little amount of current passes through the ammeter. The shunt is connected in parallel to the ammeter because of which the voltage drops across the meter and shunt remain the same. Thus, the movement of the pointer is not affected by the shunt. Let us consider that the current to be measured is I. The circuit has ammeter and shunt connected parallel to each other. The ammeter is designed for measurement of small current say, Im. The magnitude of the current I passes through the meter is very high, and it will burn the meter. So, for measuring the current I the shunt is required in the circuit. As the shunt connects in parallel with the ammeter, thus the same voltage drops occur between them:IShRSH = ImRm∴ RSH = ImRm/ISHShunt current ISH = I – ImSo, RSH = ImRm/(I – Im)∴ I/Im = 1 + (Rm/RSH)The ratio of the total current to the current required for the movement of the ammeter coil is called the multiplying power of the shunt.∴ The multiplying power = m = I/ImRSH = Rm / (m – 1)The following are the requirements of the shunt.• The resistance of the shunt should remain constant with time.• The temperature of the material should remain the same even though substantial current flows through the circuit.Materials used for making shunt of DC and AC ammeter are respectively

A metal rod is forced to move with constant velocity along two parallel metal rails, connected with a strip of metal at one end across a magnetic field (B) of 0.5 T, pointing out of the page. The rod is of length 45 cm and the speed of the rod is 70 cm/s. The rod has a resistance of 10 Ω and the resistance of the rails and connector is negligible. What is the rate at which energy is being transferred to thermal energy?a)0.225 Wb)22.55 Wc)2.25 × 10-4 Wd)2.25 × 10-3 WCorrect answer is option 'D'. Can you explain this answer?
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A metal rod is forced to move with constant velocity along two parallel metal rails, connected with a strip of metal at one end across a magnetic field (B) of 0.5 T, pointing out of the page. The rod is of length 45 cm and the speed of the rod is 70 cm/s. The rod has a resistance of 10 Ω and the resistance of the rails and connector is negligible. What is the rate at which energy is being transferred to thermal energy?a)0.225 Wb)22.55 Wc)2.25 × 10-4 Wd)2.25 × 10-3 WCorrect answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A metal rod is forced to move with constant velocity along two parallel metal rails, connected with a strip of metal at one end across a magnetic field (B) of 0.5 T, pointing out of the page. The rod is of length 45 cm and the speed of the rod is 70 cm/s. The rod has a resistance of 10 Ω and the resistance of the rails and connector is negligible. What is the rate at which energy is being transferred to thermal energy?a)0.225 Wb)22.55 Wc)2.25 × 10-4 Wd)2.25 × 10-3 WCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal rod is forced to move with constant velocity along two parallel metal rails, connected with a strip of metal at one end across a magnetic field (B) of 0.5 T, pointing out of the page. The rod is of length 45 cm and the speed of the rod is 70 cm/s. The rod has a resistance of 10 Ω and the resistance of the rails and connector is negligible. What is the rate at which energy is being transferred to thermal energy?a)0.225 Wb)22.55 Wc)2.25 × 10-4 Wd)2.25 × 10-3 WCorrect answer is option 'D'. Can you explain this answer?.
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