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Which one of the following is correct if we differentiate the equation xy = aex + be-x two times?
  • a)
    x(d2y/ dx) + 2(dy/dx) = xy
  • b)
    x(d2y/ dx) – 2(dy/dx) = xy
  • c)
    3x(d2y/ dx) + 2(dy/dx) = xy
  • d)
    x(d2y/ dx) + 2(dy/dx) = 2xy
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Which one of the following is correct if we differentiate the equation...
We have xy = aex + be-x ……(1)
Differentiating (1) with respect to x, we get
x(dy/dx) + y = aex + be-x …..(2)
Differentiating (2) now, with respect to x, we get
x(d2y/ dx) + dy/dx + dy/dx = aex + be-x
From (1),
aex + be-x = xy, so that we get
x(d2y/ dx) + 2(dy/dx) = xy
which is the required differential equation.
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Community Answer
Which one of the following is correct if we differentiate the equation...
2(dy/dx) + 2y = xyb)
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Which one of the following is correct if we differentiate the equation xy = aex+ be-xtwo times?a)x(d2y/ dx) + 2(dy/dx) = xyb)x(d2y/ dx) – 2(dy/dx) = xyc)3x(d2y/ dx) + 2(dy/dx) = xyd)x(d2y/ dx) + 2(dy/dx) = 2xyCorrect answer is option 'A'. Can you explain this answer?
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Which one of the following is correct if we differentiate the equation xy = aex+ be-xtwo times?a)x(d2y/ dx) + 2(dy/dx) = xyb)x(d2y/ dx) – 2(dy/dx) = xyc)3x(d2y/ dx) + 2(dy/dx) = xyd)x(d2y/ dx) + 2(dy/dx) = 2xyCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Which one of the following is correct if we differentiate the equation xy = aex+ be-xtwo times?a)x(d2y/ dx) + 2(dy/dx) = xyb)x(d2y/ dx) – 2(dy/dx) = xyc)3x(d2y/ dx) + 2(dy/dx) = xyd)x(d2y/ dx) + 2(dy/dx) = 2xyCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which one of the following is correct if we differentiate the equation xy = aex+ be-xtwo times?a)x(d2y/ dx) + 2(dy/dx) = xyb)x(d2y/ dx) – 2(dy/dx) = xyc)3x(d2y/ dx) + 2(dy/dx) = xyd)x(d2y/ dx) + 2(dy/dx) = 2xyCorrect answer is option 'A'. Can you explain this answer?.
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