A ball of 80mg mass and a 2*10-8 charge is hung with a thread in a uni...
Given:
Mass of the ball, m = 80mg
Charge on the ball, q = 2×10^-8 C
Electric field, E = 2×10^4 V/m
To find:
The angle made by the thread with vertical, θ.
Solution:
Let T be the tension in the thread.
The gravitational force acting on the ball is given by,
Fg = mg
where g is the acceleration due to gravity.
The electrostatic force acting on the ball is given by,
Fe = qE
where E is the electric field.
At equilibrium, the net force on the ball is zero.
Therefore, Tsinθ = Fg and Tcosθ = Fe
Substituting the values, we get
Tsinθ = mg
Tcosθ = qE
Dividing the above equations, we get
tanθ = (qE)/mg
Substituting the values, we get
tanθ = [(2×10^-8 C)×(2×10^4 V/m)]/(80×10^-6 kg×9.8 m/s^2)
tanθ = 0.27
Taking the inverse tangent on both sides, we get
θ = tan^-1(0.27)
θ = 27°
Therefore, the angle made by the thread with vertical is 27°.
Hence, option (a) is the correct answer.
A ball of 80mg mass and a 2*10-8 charge is hung with a thread in a uni...
According to the diagram, Tsinθ = Eq; Tcosθ = mg. Where T is the tension in the thread, m is the mass of the ball, E is the electric field and q is the charge of the ball. Dividing these two, we get tanθ = Eq/mg. Now substituting the value of E=2*10
4V/m, m=80mg, q=2*10
-8C, g=9.8m/s
2, we get tanθ = 25/49. Therefore θ=27 degree.