An electron of mass m is kept in a vertical electric field of magnitude E. What must be the value of E so that the electron doesn’t fall due to gravity?a)m*g*eb)e/(m*g)c)(m*g)/ed)1/(m*g*e)Correct answer is option 'C'. Can you explain this answer?

Question

An electron of mass m is kept in a vertical electric field of magnitude E. What must be the value of E so that the electron doesn&rsquo;t fall due to gravity?a)m*g*eb)e/(m*g)c)(m*g)/ed)1/(m*g*e)Correct answer is option 'C'. Can you explain this answer?

Answer

't fall down due to gravity?

The force on the electron due to the electric field is given by F = qE, where q is the charge of the electron. The force on the electron due to gravity is given by F = mg, where g is the acceleration due to gravity. For the electron to be in equilibrium, these two forces must balance each other:

qE = mg

Solving for E, we get:

E = mg/q

The mass of an electron is approximately 9.11 x 10^-31 kg, and the charge of an electron is approximately 1.6 x 10^-19 C. The acceleration due to gravity is approximately 9.8 m/s^2. Substituting these values, we get:

E = (9.11 x 10^-31 kg) x (9.8 m/s^2) / (1.6 x 10^-19 C)

E = 5.62 x 10^-12 N/C

Therefore, the value of E must be 5.62 x 10^-12 N/C so that the electron doesn't fall down due to gravity.

Answer

Gravitational force on the electron is m*g (weight of the electron). Electrical force on the body is e*E. If the electron doesn’t fall then these two forces balance each other, so m*g = E*e. Therefore E= (m*g)/e

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