Oxygen is present in a flask of 1.12L capacity at a pressure of 7.6×10^-10mm of Hg at 0 degree's Celsius.the number of oxygen molecules in the flask is

Question

Answer

5×10^12  PV=NRT/No

Answer

Pv=nRtn = pv/ Rt   = 0.0499 × 10^ - 12no of molecules = moles × NA Ans = 3.00 × 10^ 10

Answer

NOTE THIS STEP :

First we should calculate the number of moles of the gas under the given condition by the relation PV = nRT

Here P = 7.6 * 10^-10 mm Hg

= 7.6 *10^-10/760 atm. = 1 * 10^-12 atm.

V = 1.2 litre

T = 273 + 0 = 273K

R = 0.082 litre atm./K/mol

Putting the values in equation

n = PV/RT = 1 *10^-12 *1.2/0.082 *273 moles

now since 1 mole = 6.023 * 10²³ molecules

1.2*10^-12/0.082 *273 moles =1.2* 6.023 *10²³ *10^-12/0.082 *273 molecules

= 3.24 * 10¹⁰ molecules

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