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Differentiate (log2x)sin3x with respect to x.a)(3 cos3x log(log2x)+(sin3x/xlog2x)b)log2xsin3x(3cos3xlog(log2x)+(sin3x/xlog2x)c)–(3cos3xlog(log2x)+(sin3x/xlog2x)d)Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Differentiate (log2x)sin3x with respect to x.a)(3 cos3x log(log2x)+(sin3x/xlog2x)b)log2xsin3x(3cos3xlog(log2x)+(sin3x/xlog2x)c)–(3cos3xlog(log2x)+(sin3x/xlog2x)d)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Differentiate (log2x)sin3x with respect to x.a)(3 cos3x log(log2x)+(sin3x/xlog2x)b)log2xsin3x(3cos3xlog(log2x)+(sin3x/xlog2x)c)–(3cos3xlog(log2x)+(sin3x/xlog2x)d)Correct answer is option 'B'. Can you explain this answer?.

Solutions for Differentiate (log2x)sin3x with respect to x.a)(3 cos3x log(log2x)+(sin3x/xlog2x)b)log2xsin3x(3cos3xlog(log2x)+(sin3x/xlog2x)c)–(3cos3xlog(log2x)+(sin3x/xlog2x)d)Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

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