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A compound ‘P’ on treating with concentrated H2SO4 forms ‘R’. The product ‘R’ on heating at 460K forms a zwitter ionic compound. Identify P, R respectively.
  • a)
    Aniline; anilinium hydrogensulphate
  • b)
    Aniline; sulphanilic acid
  • c)
    Anilinium hydrogensulphate; sulphanilic acid
  • d)
    Sulphanilic acid; anilinium hydrogensulphate
Correct answer is option 'A'. Can you explain this answer?
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A compound ‘P’ on treating with concentrated H2SO4 forms &...
Aniline (P) reacts with conc. H2SO4 to form anilinium hydrogensulphate (R) which on heating at 453-473K produces sulphanilic acid (zwitter ionic compound).
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A compound ‘P’ on treating with concentrated H2SO4 forms ‘R’. The product ‘R’ on heating at 460K forms a zwitter ionic compound. Identify P, R respectively.a)Aniline; anilinium hydrogensulphateb)Aniline; sulphanilic acidc)Anilinium hydrogensulphate; sulphanilic acidd)Sulphanilic acid; anilinium hydrogensulphateCorrect answer is option 'A'. Can you explain this answer?
Question Description
A compound ‘P’ on treating with concentrated H2SO4 forms ‘R’. The product ‘R’ on heating at 460K forms a zwitter ionic compound. Identify P, R respectively.a)Aniline; anilinium hydrogensulphateb)Aniline; sulphanilic acidc)Anilinium hydrogensulphate; sulphanilic acidd)Sulphanilic acid; anilinium hydrogensulphateCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A compound ‘P’ on treating with concentrated H2SO4 forms ‘R’. The product ‘R’ on heating at 460K forms a zwitter ionic compound. Identify P, R respectively.a)Aniline; anilinium hydrogensulphateb)Aniline; sulphanilic acidc)Anilinium hydrogensulphate; sulphanilic acidd)Sulphanilic acid; anilinium hydrogensulphateCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound ‘P’ on treating with concentrated H2SO4 forms ‘R’. The product ‘R’ on heating at 460K forms a zwitter ionic compound. Identify P, R respectively.a)Aniline; anilinium hydrogensulphateb)Aniline; sulphanilic acidc)Anilinium hydrogensulphate; sulphanilic acidd)Sulphanilic acid; anilinium hydrogensulphateCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A compound ‘P’ on treating with concentrated H2SO4 forms ‘R’. The product ‘R’ on heating at 460K forms a zwitter ionic compound. Identify P, R respectively.a)Aniline; anilinium hydrogensulphateb)Aniline; sulphanilic acidc)Anilinium hydrogensulphate; sulphanilic acidd)Sulphanilic acid; anilinium hydrogensulphateCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of A compound ‘P’ on treating with concentrated H2SO4 forms ‘R’. The product ‘R’ on heating at 460K forms a zwitter ionic compound. Identify P, R respectively.a)Aniline; anilinium hydrogensulphateb)Aniline; sulphanilic acidc)Anilinium hydrogensulphate; sulphanilic acidd)Sulphanilic acid; anilinium hydrogensulphateCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A compound ‘P’ on treating with concentrated H2SO4 forms ‘R’. The product ‘R’ on heating at 460K forms a zwitter ionic compound. Identify P, R respectively.a)Aniline; anilinium hydrogensulphateb)Aniline; sulphanilic acidc)Anilinium hydrogensulphate; sulphanilic acidd)Sulphanilic acid; anilinium hydrogensulphateCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A compound ‘P’ on treating with concentrated H2SO4 forms ‘R’. The product ‘R’ on heating at 460K forms a zwitter ionic compound. Identify P, R respectively.a)Aniline; anilinium hydrogensulphateb)Aniline; sulphanilic acidc)Anilinium hydrogensulphate; sulphanilic acidd)Sulphanilic acid; anilinium hydrogensulphateCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A compound ‘P’ on treating with concentrated H2SO4 forms ‘R’. The product ‘R’ on heating at 460K forms a zwitter ionic compound. Identify P, R respectively.a)Aniline; anilinium hydrogensulphateb)Aniline; sulphanilic acidc)Anilinium hydrogensulphate; sulphanilic acidd)Sulphanilic acid; anilinium hydrogensulphateCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A compound ‘P’ on treating with concentrated H2SO4 forms ‘R’. The product ‘R’ on heating at 460K forms a zwitter ionic compound. Identify P, R respectively.a)Aniline; anilinium hydrogensulphateb)Aniline; sulphanilic acidc)Anilinium hydrogensulphate; sulphanilic acidd)Sulphanilic acid; anilinium hydrogensulphateCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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