In chemistry, the terms "oxidation" and "reduction" refer to reactions in which an atom (or group of atoms) loses or gains electrons, respectively. Oxidation numbers are numbers assigned to atoms (or groups of atoms) that help chemists keep track of how many electrons are available for transfer and whether given reactants are oxidized or reduced in a reaction. The process of assigning oxidation numbers to atoms can range from remarkably simple to somewhat complex, based on the charge of the atoms and the chemical composition of the molecules they are a part of. To complicate matters, some elements can have more than one oxidation number. Luckily, the assignment of oxidation numbers is governed by well-defined, easy-to follow rules, though knowledge of basic chemistry and algebra will make navigation of these rules much easier.
Determine whether the substance in question is elemental. Free, uncombined elemental atoms always have an oxidation number of 0. This is true both for atoms whose elemental form is composed of a lone atom, as well as atoms whose elemental form is diatomic or polyatomic.
For example, Al(s) and Cl2 both have oxidation numbers of 0 because they are in their uncombined elemental forms.
Note that sulfur's elemental form, S8, or octasulfur, though irregular, also has an oxidation number of 0.
Determine whether the substance in question is an ion. Ions have oxidation numbers equal to their charge. This is true both for ions that are not bound to any other elements as well as for ions that form part of an ionic compound.
For instance, the ion Cl- has an oxidation number of -1.
The Cl ion still has an oxidation number of -1 when it's part of the compound NaCl. Because the Na+ ion, by definition, has a charge of +1, we know that the Cl- ion has a charge of -1, so its oxidation number is still -1.