An old lady spent one twelfth of her life as a child and one seventh w...
Age spent as child = X/12
Age spent as a teenager = X/7
Age spent between adulthood and marriage = X/6
Age of daughter = X – (X/12 + X/7 + X/6 + 3 + 6) = X - 33X/84 – 9 = 51X/84 – 9
Now, 2(51X/84 – 9) = X
Or 18X/84 = 18
Or X = 84.
Age of daughter = X/2 = 42 years
An old lady spent one twelfth of her life as a child and one seventh w...
Live?
Let's assume the lady lived for x years.
According to the given information:
- One twelfth of her life was spent as a child, so she spent x/12 years as a child.
- One seventh of her life was spent as a teenager, so she spent x/7 years as a teenager.
- One sixth of her life was spent between the time she became an adult and the time she married, so she spent x/6 years in that period.
- Three years after marriage her daughter was born and the daughter died six years before she died. So, the daughter lived for (x - 3 - 6) = (x - 9) years.
We are also given that the lady lived to be twice as old as her daughter did. Therefore, the lady lived for 2*(x - 9) years.
We can add up all the periods of her life to get x/12 + x/7 + x/6 + 3 + 6 + (x - 9) = 2*(x - 9).
Combining like terms, we get:
7x + 12x + 14x + 252 + 84 + 12 = 24x - 18.
Simplifying, we get:
33x + 348 = 24x - 18.
Subtracting 24x and 348 from both sides, we get:
9x = -366.
Dividing by 9 on both sides, we get:
x = -366/9.
However, it is not possible for someone to have negative years in their life. Therefore, there seems to be an error in the given information or assumptions made.
Hence, we cannot determine how long the lady lived based on the given information.