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At a specific rate of simple interest, a sum doubles itself in 5 years. In how many years will it becomes four times itself?
  • a)
    18 years
  • b)
    15 years
  • c)
    12 years
  • d)
    16 years 
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
At a specific rate of simple interest, a sum doubles itself in 5 years...
Let the principal be Rs. 100, Time = 5 years
∴ Amount = Rs. 200
Interest = (200-100) = Rs. 100

Now amount = Rs. 400
∴ Interest = (400 – 100) = Rs. 300 
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Community Answer
At a specific rate of simple interest, a sum doubles itself in 5 years...
Given Information:
- The sum doubles itself in 5 years at a specific rate of simple interest.

Calculating the rate of interest:
- Let the principal amount be P and the rate of interest be R%.
- According to the question, the sum doubles itself in 5 years. Therefore, the amount after 5 years will be 2P.
- Using the simple interest formula: A = P(1 + (R/100)*T), where A is the amount, P is the principal amount, R is the rate of interest, and T is the time.
- Substituting the given values: 2P = P(1 + (R/100)*5)
- Solving for R, we get R = 20%.

Time taken to become four times the principal:
- To find the time taken for the sum to become four times itself, we can use the formula for simple interest: A = P(1 + (R/100)*T).
- Let the time taken be 't' years. Therefore, the amount after 't' years will be 4P.
- Substituting the values into the formula: 4P = P(1 + (20/100)*t)
- Solving for t, we get t = 15 years.
Therefore, it will take 15 years for the sum to become four times itself at the given rate of simple interest. Hence, the correct answer is option (b) 15 years.
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At a specific rate of simple interest, a sum doubles itself in 5 years. In how many years will it becomes four times itself?a)18 yearsb)15 yearsc)12 yearsd)16 yearsCorrect answer is option 'B'. Can you explain this answer?
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