4 men and 6 women complete a piece of work in 8 days while 3 men and 7...
Given:
- 4 men and 6 women complete a piece of work in 8 days
- 3 men and 7 women complete the same work in 10 days
Let's assume that the amount of work done by each person in one day is the same.
Let's first find the amount of work done by each man and each woman in one day.
Let the work done by each man in one day be M, and the work done by each woman in one day be W.
From the given information, we can write the following equations:
4M + 6W = 1 (Equation 1) - Since 4 men and 6 women complete the work in 8 days
3M + 7W = 1 (Equation 2) - Since 3 men and 7 women complete the work in 10 days
Solving these equations will give us the values of M and W.
Multiplying Equation 1 by 3 and Equation 2 by 4, we get:
12M + 18W = 3 (Equation 3)
12M + 28W = 4 (Equation 4)
Subtracting Equation 3 from Equation 4, we get:
10W = 1
Therefore, W = 1/10
Substituting the value of W in Equation 1, we get:
4M + 6(1/10) = 1
4M + 3/5 = 1
4M = 1 - 3/5
4M = 2/5
M = 1/10
So, the work done by each man in one day is 1/10 and the work done by each woman in one day is 1/10.
Now, let's find how many days it will take for 10 women to complete the work.
Let the number of days required be D.
From the given information, we can write the equation:
10(1/10)D = 1
Simplifying, we get:
D = 1
Therefore, it will take 10 women 1 day to complete the work.
Since the options provided are in terms of days, the closest answer is 40 days (option D).
Hence, the correct answer is D) 40 days.
4 men and 6 women complete a piece of work in 8 days while 3 men and 7...
Let 1 man's 1 day work be x and 1 woman's 1 day work be y. then
4x+6 y= 1/8 ...(1)
3x+7y = 1/10 ...(2)
Multiplying (1) by 3, (2) by 4 and subtracting, we get
10 y = (4/10- 3/8)
= (16-15)/40 = 1/40
⇒ y = 1/400
1 woman's 1 day work = 1/400
10 women's 1 day work = (1/400*10) = 1/40
Hence 10 women can finish the work in 40 days