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Will the following C code compile without any error?
#include <stdio.h>
    int main()
    {
        int k;
        {
            int k;
            for (k = 0; k < 10; k++);
        }
    }
  • a)
    Yes
  • b)
    No
  • c)
    Depends on the compiler
  • d)
    Depends on the C standard implemented by compilers
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Will the following C code compile without any error?#include <stdio...
There can be blocks inside the block. But within a block, variables have only block scope.
Output:
$ cc pgm5.c
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Community Answer
Will the following C code compile without any error?#include <stdio...

Explanation:

Scope of Variables:
- In the given code, there are two variables named 'k' declared in different scopes.
- The outer 'k' variable is declared in the main function, while the inner 'k' variable is declared inside the block enclosed by curly braces.

Inner Variable:
- The inner 'k' variable declared inside the block is a separate variable from the outer 'k' variable.
- This inner 'k' variable is local to the block and its scope is limited to that block only.

For Loop:
- Inside the inner block, there is a for loop that uses the inner 'k' variable to iterate from 0 to 9.
- This for loop does not have any statements inside the loop body, so it will simply increment the 'k' variable from 0 to 9 and then terminate.

Compilation:
- The code will compile without any error because each variable is declared in a separate scope, and there is no conflict between them.
- The inner 'k' variable is used only within the block where it is declared, and it does not affect the outer 'k' variable.

Therefore, the given C code will compile without any error.
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