Pls justify the answer. :- Na2Cr2O7 is less soluble than K2Cr2O7 ? How...
Solubility of Na2Cr2O7 and K2Cr2O7
Introduction:
When comparing the solubility of two compounds, it is important to consider their chemical structures and the nature of the solvent. In this case, we are comparing the solubility of sodium dichromate (Na2Cr2O7) and potassium dichromate (K2Cr2O7). Both compounds are salts of dichromic acid (H2Cr2O7) and contain the dichromate ion (Cr2O7^2-).
Factors Affecting Solubility:
The solubility of a compound depends on several factors, including temperature, pressure, and the nature of the solvent. In this case, we will focus on the effect of the solvent on the solubility of Na2Cr2O7 and K2Cr2O7.
Lattice Energy:
Lattice energy is a measure of the strength of the forces holding the ions in a solid lattice structure. It is inversely related to solubility, meaning that compounds with higher lattice energies tend to be less soluble.
Size and Charge of the Ion:
The size and charge of the ions in a compound also affect its solubility. Smaller ions tend to have higher solubility than larger ions because they can more easily fit into the solvent's lattice structure. Additionally, ions with higher charges tend to have lower solubility because they experience stronger electrostatic attractions within the lattice.
Comparison:
Solubility of Na2Cr2O7:
- Sodium ions (Na+) are larger than potassium ions (K+), which makes it more difficult for them to fit into the solvent's lattice structure.
- Sodium ions have a +1 charge, while dichromate ions have a -2 charge. The higher charge of the dichromate ion leads to stronger electrostatic attractions within the lattice, reducing solubility.
- Therefore, Na2Cr2O7 has higher lattice energy and lower solubility compared to K2Cr2O7.
Solubility of K2Cr2O7:
- Potassium ions (K+) are smaller than sodium ions (Na+), allowing them to more easily fit into the solvent's lattice structure.
- Potassium ions have a +1 charge, similar to sodium ions, but the electrostatic attraction between potassium and dichromate ions is not as strong as in the case of Na2Cr2O7.
- As a result, K2Cr2O7 has lower lattice energy and higher solubility compared to Na2Cr2O7.
Conclusion:
In conclusion, Na2Cr2O7 is less soluble than K2Cr2O7 due to the larger size and higher charge of sodium ions, leading to higher lattice energy and weaker solubility. On the other hand, K2Cr2O7 has smaller ions and lower lattice energy, resulting in higher solubility.
Pls justify the answer. :- Na2Cr2O7 is less soluble than K2Cr2O7 ? How...
Solubility of dichromates of alkali metals decreases on going down the group due to decrease in hydration enthalpy down the group is higher than decrease in lattice enthalpy... hence lattice enthalpy on going down the group will be less readily compensated by hydration enthalpy hence solubility decreases..