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Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case?
- a)1020
- b)1026
- c)1022
- d)1030
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves ...
Lowest 4-digit number is 1000.
LCM of 3, 4 and 5 = |3, 4, 5
As we saw above no two numbers are divisible by common factor so their LCM is their
product.
LCM of 3, 4 and 5 = 3 x 4 x 5 = 60.
Dividing 1000 by 60, we get the remainder 40.
Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.
Now, add the remainder 2 that's required. Thus, the answer is (1020 + 2 = 1022).
LCM of 3, 4 and 5 = |3, 4, 5
As we saw above no two numbers are divisible by common factor so their LCM is their
product.
LCM of 3, 4 and 5 = 3 x 4 x 5 = 60.
Dividing 1000 by 60, we get the remainder 40.
Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.
Now, add the remainder 2 that's required. Thus, the answer is (1020 + 2 = 1022).
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Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case?a)1020b)1026c)1022d)1030Correct answer is option 'C'. Can you explain this answer?
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