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Find the blanking force required to punch 10 mm diameter holes in a steel sheet of 3 mm thickness. Given shear strength of material = 400 MPa, penetration = 40% and shear provided on the punch = 2 mm.
  • a)
    22.6 kN
  • b)
    37.7 kN
  • c)
    61.6 kN
  • d)
    94.3 kN
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Find the blanking force required to punch 10 mm diameter holes in a st...
Given data:
Diameter of hole (d) = 10 mm
Thickness of sheet (t) = 3 mm
Shear strength of material (τ) = 400 MPa
Penetration (P) = 40%
Shear provided on the punch (S) = 2 mm

Formula used:
Blanking force (F) = π/4 * d^2 * t * τ / [(1 - P^2) * S]

Calculation:
Substituting the given values in the formula, we get:
F = π/4 * (10)^2 * 3 * 400 / [(1 - 0.4^2) * 2]
F = 22.6 kN

Therefore, the blanking force required to punch 10 mm diameter holes in a steel sheet of 3 mm thickness is 22.6 kN.
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