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A particle moves in a straight line with a uniform acceleration 'a' .initial velocity of the particle is zero. find the average velocity of the particle in first 'S' distance.
Most Upvoted Answer
A particle moves in a straight line with a uniform acceleration 'a' .i...
V=√2as, u=0, then find average speed (v+u)/2 so ..{(√2as)+0} /2=(√as/2)
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A particle moves in a straight line with a uniform acceleration 'a' .i...
Problem: A particle moves in a straight line with a uniform acceleration 'a' .initial velocity of the particle is zero. Find the average velocity of the particle in the first 'S' distance.

Solution:

Formula: The average velocity of the particle in the first 'S' distance is given as:

v_avg = (v_f + v_i) / 2

where
v_f = final velocity of the particle
v_i = initial velocity of the particle
S = distance travelled by the particle

Derivation:

We know that the particle is moving with uniform acceleration 'a', so we can use the following formulae:

v_f = u + at ---(1)
S = ut + (1/2)at^2 ---(2)

where
u = initial velocity of the particle
t = time taken by the particle to cover the distance 'S'

From equation (1), we get:

v_f = at ---(3)

Substituting equation (3) in equation (2), we get:

S = (1/2)at^2 ---(4)

From equation (4), we get:

t = sqrt(2S/a) ---(5)

Substituting equation (3) and (5) in the formula for average velocity, we get:

v_avg = (at + 0) / 2

v_avg = (a * sqrt(2S/a)) / 2

Final Answer:

Therefore, the average velocity of the particle in the first 'S' distance is (a * sqrt(2S/a)) / 2.
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