Value of x in pair of linear equations 36x + 24y = 702 and 24x + 36y =...
We have, 36x + 24y = 702
and 24x + 36y = 558
Simplifying above equations, we get
6x + 4y = 117 ...(1) and 4x + 6y = 93 ...(2)
Multiplying eq. (1) by 3, eq. (2) by –2 and then adding, we get 18x + 12y – 8x – 12y = 351 – 186
⇒ 10x = 165 ⇒ x =

Value of x in pair of linear equations 36x + 24y = 702 and 24x + 36y =...
To find the value of x in the given pair of linear equations, we can use the method of substitution or elimination. Let's use the method of substitution to solve these equations.
Given equations:
1) 36x + 24y = 702
2) 24x + 36y = 558
Step 1: Solve one equation for one variable in terms of the other variable.
Let's solve equation 1) for x:
36x = 702 - 24y
Dividing both sides by 36:
x = (702 - 24y)/36
Step 2: Substitute the value of x in equation 2) with the expression we obtained in step 1.
24[(702 - 24y)/36] + 36y = 558
Simplifying this equation:
(24 * 702 - 24 * 24y + 36 * 36y)/36 = 558
(16848 - 576y + 1296y)/36 = 558
(16848 + 720y)/36 = 558
16848 + 720y = 558 * 36
16848 + 720y = 20088
720y = 20088 - 16848
720y = 3240
Dividing both sides by 720:
y = 3240/720
y = 18/4
y = 9/2
Step 3: Substitute the value of y back into equation 1) to find the value of x.
36x + 24(9/2) = 702
36x + 216/2 = 702
36x + 108 = 702
36x = 702 - 108
36x = 594
Dividing both sides by 36:
x = 594/36
x = 33/2
Therefore, the value of x is 33/2, which matches option A) 33/2.