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Y = log [ a bsinx / absinx ] , find dy/dx?
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Y = log [ a bsinx / absinx ] , find dy/dx?
Solution:


Step 1: Use the logarithmic differentiation formula


We are given the function Y = log [ a bsinx / absinx ].

Using the logarithmic differentiation formula, we can find the derivative of Y with respect to x as:

dY/dx = [1 / ( a bsinx / absinx ) ] * [ d / dx ( a bsinx / absinx ) ]

Step 2: Simplify the expression inside the derivative


Now, we need to simplify the expression inside the derivative.

a and b are constants, so we can take them outside the derivative:

dY/dx = [1 / ( a bsinx / absinx ) ] * [ a b * d / dx (sinx / sinx) ]

Now, we can simplify the expression inside the derivative as follows:

sinx / sinx = 1

So, the derivative becomes:

dY/dx = [1 / ( a bsinx / absinx ) ] * [ a b * d / dx (1) ]

Step 3: Evaluate the derivative


The derivative of 1 with respect to x is 0, so the expression inside the derivative becomes 0:

dY/dx = [1 / ( a bsinx / absinx ) ] * 0

dY/dx = 0

Step 4: Interpret the result


The derivative of Y with respect to x is 0. This means that Y is a constant with respect to x. Therefore, the graph of Y is a horizontal line, and there is no slope at any point.

In other words, the function Y does not change as x changes. This result may seem surprising, but it is a consequence of the way the function is defined.

Final Answer:


dy/dx = 0.
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Y = log [ a bsinx / absinx ] , find dy/dx?
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Y = log [ a bsinx / absinx ] , find dy/dx? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Y = log [ a bsinx / absinx ] , find dy/dx? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Y = log [ a bsinx / absinx ] , find dy/dx?.
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