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An iron ball of radius 0.3m falling through a column of oil density 0.94g/cm^3 attains a terminal velocity of 0.5m/s. what is the coefficient of viscosity of the oil? density of iron is 7.8g/cm^3
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Most Upvoted Answer
An iron ball of radius 0.3m falling through a column of oil density 0....
Calculation of Coefficient of Viscosity of Oil


Given Data


  • Radius of iron ball, r = 0.3m

  • Density of oil, ρ = 0.94g/cm³

  • Terminal velocity of ball, v = 0.5m/s

  • Density of iron, ρiron = 7.8g/cm³



Formula

Terminal velocity of a sphere falling through a fluid is given by:

v = (2/9) (r2 g (ρiron - ρ) / η)

where η is the coefficient of viscosity of the oil


Calculation

Substituting the given values in the formula:

0.5 = (2/9) (0.32 x 9.8 x (7.8 - 0.94) / η)

η = (2/9) (0.32 x 9.8 x (7.8 - 0.94) / 0.5)

η = 0.12 Pa s


Answer

Therefore, the coefficient of viscosity of the oil is 0.12 Pa s.
Community Answer
An iron ball of radius 0.3m falling through a column of oil density 0....
The direct formula is..v=2r^2g(rho-sigma)/(9eta)....eta= coefficient of viscosity..v= terminal velocity
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Attempt All sub parts from each question.Newtonian and non-Newtonian fluid: Viscosity is the physical property that characterizes the flow resistance of simple fluids. Newton’s law of viscosity defines the relationship between the shear stress and shear rate of a fluid subjected to a mechanical stress. The ratio of shear stress to shear rate is a constant, for a given temperature and pressure, and is defined as the viscosity or coefficient of viscosity. Newtonian fluids obey Newton’s law of viscosity. The viscosity is independent of the shear rate. Example: air, water, alcohol etc. Non-Newtonian fluids do not follow Newton’s law thus, their viscosity (ratio of shear stress to shear rat e) is not constant and is dependent on the shear rate. Example: honey, ketchup etc. Non-Newtonian fluids can be categorized into four types based on the way a fluid’s viscosity changes in response to variations in shear rate.• Pseudoplastic: Materials whose viscosity decreases as the shear rate increases. This type of flow behavior is sometimes called shear thinning. Example: Cake batter, agar-agar and fruit juice concentrates, nail polish etc.• Dilatant: M aterials whose viscosity increases as the shear rate increases. This type of behavior is sometimes called shear-thickening. Example: Suspension of corn starch in water and candy compounds etc..• Thixotropic: M aterials whose viscosity decreases when sheared at a constant rate over time. Example: Yogurt, gelatin gel, honey etc.• Rheopectic: M aterials whose viscosity increases when sheared at a constant rate over time. Example: Printer ink, gypsum paste etc.Q. Newton’s law of viscosity states

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An iron ball of radius 0.3m falling through a column of oil density 0.94g/cm^3 attains a terminal velocity of 0.5m/s. what is the coefficient of viscosity of the oil? density of iron is 7.8g/cm^3
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An iron ball of radius 0.3m falling through a column of oil density 0.94g/cm^3 attains a terminal velocity of 0.5m/s. what is the coefficient of viscosity of the oil? density of iron is 7.8g/cm^3 for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An iron ball of radius 0.3m falling through a column of oil density 0.94g/cm^3 attains a terminal velocity of 0.5m/s. what is the coefficient of viscosity of the oil? density of iron is 7.8g/cm^3 covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An iron ball of radius 0.3m falling through a column of oil density 0.94g/cm^3 attains a terminal velocity of 0.5m/s. what is the coefficient of viscosity of the oil? density of iron is 7.8g/cm^3.
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