A line segment AB of length 2 moves with it's ends on the axes .the lo...
The locus of a point is the set of all points that the point can occupy over a period of time or under certain conditions. In this case, the point P is dividing the line segment AB into two parts of equal length, with the ratio 1:1.
If the line segment AB is moving with its ends on the axes, and point P is dividing it into two parts of equal length, then the locus of point P will be a line that is perpendicular to AB and passes through the midpoint of AB.
To find the length of the line segment AB, you can use the Pythagorean Theorem:
AB = √(x2 - x1)2 + (y2 - y1)2
= √(02 - 02)2 + (02 - (-2))2
= √(00)2 + (2)2
= √(4)
= 2
The midpoint of AB is the point that divides the line segment into two parts of equal length, and it is located at the coordinates (0, 0).
So, the locus of point P will be a line that is perpendicular to AB and passes through the midpoint of AB, which is located at (0, 0). This line will be a straight line that is parallel to one of the axes.