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A 4.925 g sample of a mixture of CuCl and CuB*r_{2} was dissolved in water and mixed thoroughly with a 5.74 g portion of AgCl. After the reaction the solid, a mixture of AgCl and AgBr was filtered, washed, and dried. Its mass was found to be 6.63 g.?
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A 4.925 g sample of a mixture of CuCl and CuB*r_{2} was dissolved in w...
Problem Statement:
A 4.925 g sample of a mixture of CuCl and CuBr2 was dissolved in water and mixed thoroughly with a 5.74 g portion of AgCl. After the reaction, the solid, a mixture of AgCl and AgBr was filtered, washed, and dried. Its mass was found to be 6.63 g. Explain in detail.

Solution:

Step 1: Write balanced chemical equations for the reactions:

CuCl + AgCl → CuCl2 + AgCl
CuBr2 + 2AgCl → 2AgBr + CuCl2

Step 2: Calculate the moles of AgCl used:

Moles of AgCl = mass / molar mass = 5.74 g / 143.32 g/mol = 0.04 mol

Step 3: Determine the limiting reactant:

For CuCl and AgCl reaction: 1 mol CuCl : 2 mol AgCl
Moles of CuCl = 0.04 mol / 2 = 0.02 mol

For CuBr2 and AgCl reaction: 1 mol CuBr2 : 2 mol AgCl
Moles of CuBr2 = 0.04 mol / 2 = 0.02 mol

Since the moles of CuCl and CuBr2 are equal, we need to compare the masses of CuCl2 and AgBr formed to determine the limiting reactant.

Step 4: Calculate the mass of CuCl2 formed:

Moles of CuCl2 = moles of CuCl = 0.02 mol
Mass of CuCl2 = moles of CuCl2 x molar mass = 0.02 mol x 134.45 g/mol = 2.69 g

Step 5: Calculate the mass of AgBr formed:

Moles of AgBr = moles of AgCl = 0.04 mol
Mass of AgBr = moles of AgBr x molar mass = 0.04 mol x 187.77 g/mol = 7.51 g

Step 6: Determine the actual mass of the mixture obtained:

Actual mass of the mixture obtained = mass of AgCl + mass of AgBr = 6.63 g

Step 7: Calculate the percent composition of CuCl and CuBr2 in the mixture:

Mass of CuCl and CuBr2 = mass of mixture obtained - mass of AgBr = 6.63 g - 7.51 g = -0.88 g (negative value indicates that there was no CuCl or CuBr2 in the sample)

Therefore, the sample only contained AgCl and AgBr, and did not contain any CuCl or CuBr2.
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A 4.925 g sample of a mixture of CuCl and CuB*r_{2} was dissolved in water and mixed thoroughly with a 5.74 g portion of AgCl. After the reaction the solid, a mixture of AgCl and AgBr was filtered, washed, and dried. Its mass was found to be 6.63 g.?
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A 4.925 g sample of a mixture of CuCl and CuB*r_{2} was dissolved in water and mixed thoroughly with a 5.74 g portion of AgCl. After the reaction the solid, a mixture of AgCl and AgBr was filtered, washed, and dried. Its mass was found to be 6.63 g.? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A 4.925 g sample of a mixture of CuCl and CuB*r_{2} was dissolved in water and mixed thoroughly with a 5.74 g portion of AgCl. After the reaction the solid, a mixture of AgCl and AgBr was filtered, washed, and dried. Its mass was found to be 6.63 g.? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 4.925 g sample of a mixture of CuCl and CuB*r_{2} was dissolved in water and mixed thoroughly with a 5.74 g portion of AgCl. After the reaction the solid, a mixture of AgCl and AgBr was filtered, washed, and dried. Its mass was found to be 6.63 g.?.
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